Answer:
{a , c}
Step-by-step explanation:
first find u intersection p
n(U n P ) = {a , b , c , d} n {b , d , e}
={d , b}
intersection means element or values which lies in both the sets
now to find p complement
note : p( bar at the top ) is read as p complement
p complement = n(U) - n(U n P)
={a , b , c , d} - {d , b}
={a , c}
n(U) -n(U n P) means the elements which is only in n(U ) but not in n(U n P)
Answer:
The inverse of the function is 
.
Step-by-step explanation:
The function provided is:
Let 
.
Then the value of <em>x</em> is:
For the inverse of the function, 
.
⇒
Compute the value of ![f[f^{-1}(x)]](https://tex.z-dn.net/?f=f%5Bf%5E%7B-1%7D%28x%29%5D)
as follows:
![f[f^{-1}(x)]=f[\frac{x-5}{3}]](https://tex.z-dn.net/?f=f%5Bf%5E%7B-1%7D%28x%29%5D%3Df%5B%5Cfrac%7Bx-5%7D%7B3%7D%5D)
![=3[\frac{x-5}{3}]+5\\\\=x-5+5\\\\=x](https://tex.z-dn.net/?f=%3D3%5B%5Cfrac%7Bx-5%7D%7B3%7D%5D%2B5%5C%5C%5C%5C%3Dx-5%2B5%5C%5C%5C%5C%3Dx)
Hence proved that ![f[f^{-1}(x)]=x](https://tex.z-dn.net/?f=f%5Bf%5E%7B-1%7D%28x%29%5D%3Dx)
.
Compute the value of ![f^{-1}[f(x)]](https://tex.z-dn.net/?f=f%5E%7B-1%7D%5Bf%28x%29%5D)
as follows:
![f^{-1}[f(x)]=f^{-1}[3x+5]](https://tex.z-dn.net/?f=f%5E%7B-1%7D%5Bf%28x%29%5D%3Df%5E%7B-1%7D%5B3x%2B5%5D)
Hence proved that ![f^{-1}[f(x)]=x](https://tex.z-dn.net/?f=f%5E%7B-1%7D%5Bf%28x%29%5D%3Dx)
.
Answer:
4+i
Step-by-step explanation:
A complex number usually took the form a+bi where a and b are real numbers and 'i' represents an imaginary number. For a quadratic equation, the complex roots for the root of a quadratic equation took the form known as complex conjugates. The complex conjugates are formed by changing the sign of the imaginary part.
SO, if a quadratic equation has 4-i as a solution, the other solution must be 4+i.
