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Delicious77 [7]
3 years ago
13

Is the figure, z || y and a is a transversal that crosses the parallel lines.

Mathematics
1 answer:
Juliette [100K]3 years ago
4 0

Answer:

d

Step-by-step explanation:

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55 is 40% of what number?
alexira [117]
40 over 100 and 55 over n cross multiply 55 x 100 and divide by 40.which gives you 137.5
4 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=%20%5Clarge%7B%5Cbold%20%5Cred%7B%20%5Csum%20%5Climits_%7B8%7D%5E%7B4%7D%20%7Bx%7D%5E%7B2%7D%2
kiruha [24]

Answer:

No solution

Step-by-step explanation:

We have

$\sum_{x=8}^{4}x^2 + 9\left(\dfrac{\cos^2(\infty)}{\sin^2(\infty)} \right)$

For the sum it is not correct to assume

$\sum_{x=8}^{4}x^2= 8^2 + 7^2+6^2+5^2+4^2 = 64+49+36+25+16 = 190$

Note that for

$\sum_{x=a}^b f(x)$

it is assumed a\leq x \leq b and in your case \nexists x\in\mathbb{Z}: a\leq x\leq b for a>b

In fact, considering a set S we have

$\sum_{x=a}^b (S \cup \varnothing) = \sum_{x=a}^b S + \sum_{x=a}^b \varnothing $ that satisfy S = S \cup \varnothing

This means that, by definition \sum_{x=a}^b \varnothing = 0

Therefore,

$\sum_{x=8}^{4}x^2 = 0$

because the sum is empty.

For

9\left(\dfrac{\cos^2(\infty)}{\sin^2(\infty)} \right)

we have other problems. Actually, this case is really bad.

Note that \cos^2(\infty) has no value. In fact, if we consider for the case

$\lim_{x \to \infty} \cos^2(x)$, the cosine function oscillates between [-1, 1] , and therefore it is undefined. Thus, we cannot evaluate

9\left(\dfrac{\cos^2(\infty)}{\sin^2(\infty)} \right)

and then

$\sum_{x=8}^{4}x^2 + 9\left(\dfrac{\cos^2(\infty)}{\sin^2(\infty)} \right)$

has no solution

7 0
2 years ago
The wildcats scored an average of 56 points per game during their four-game season. If the scores for their first three games we
Licemer1 [7]

Answer:

the team score would be 67

Step-by-step explanation:

3 0
2 years ago
Help me please, I have been struggling
ZanzabumX [31]

Answer: 4

Step-by-step explanation:

All you have to do is multiply each number 14 * 4 = 56 : 16 * 4 = 64 : and 7 * 4 = 28

3 0
3 years ago
Please help me with this question. I don't think I understand it. Quadratic functions graphing #15-19.
belka [17]

Answer:

15) (1, 1) and (-1, 1)

16) (1, 2) and (-1, 2)

17 (1,1/2) and (-1, 1/2)

18) (1,1/4) and (-1, 1/4)

19) 16 is vertical stretch, 17 and 18 is vertical compressed

Step-by-step explanation:

for qs 15-18 since x is 1 or -1 if you sq 1 or -1 you will always get 1

so y is the "a" value in the equation  y=ax²

for qs 19

y=ax²

so if a>1 -- then vertical stretch

when 0<a<1 -- then vertical compressed

   

3 0
2 years ago
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