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2 years ago

Will the square of a negative number always be positive? Explain why.

Mathematics

2 answers:

qwelly [4]2 years ago

6 0

the square of a negative number always be positive

eg: -2² = -2×-2 = (-×- = +) +4

the cube of a negative number always be positive

eg: -2³ = -2×-2×-2 = (-×-×- = +) -8

hope it helps...!!!

ExtremeBDS [4]2 years ago

3 0

Answer:

the square of a negative number always be positive

eg: -2² = -2×-2 = (-×- = +) +4

the cube of a negative number always be positive

eg: -2³ = -2×-2×-2 = (-×-×- = +) -8

Step-by-step explanation:

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The speed with which utility companies can resolve problems is very important. GTC, the Georgetown Telephone Company, reports it

brilliants [131]

Answer:

(a) 11.25 and 1.68

(b) 0.1651

(c) 0.3903

(d) 0.6865

Step-by-step explanation:

We are given that GTC, the Georgetown Telephone Company, reports it can resolve customer problems the same day they are reported in 75% of the cases and suppose the 15 cases reported today are representative of all complaints.

This situation can be represented through Binomial distribution as;

$P(X=r)= \binom{n}{r}p^{r}(1-p)^{n-r} ; x = 0,1,2,3,....$

where, n = number of trials (samples) taken = 15

r = number of success

p = probability of success which in our question is % of cases in

which customer problems are resolved on the same day, i.e.;75%

So, here X ~ $Binom(n=15,p=0.75)$

(a) Expected number of problems to be resolved today = E(X)

E(X) = $\mu$ = n * p = 15 * 0.75 = 11.25

Standard deviation = $\sigma$ = $\sqrt{n*p*(1-p)}$ = $\sqrt{15*0.75*(1-0.75)}$ = 1.68

(b) Probability that 10 of the problems can be resolved today = P(X = 10)

P(X = 10) = $\binom{15}{10}0.75^{10}(1-0.75)^{15-10}$

= $3003*0.75^{10} *0.25^{5}$ = 0.1651

= $\binom{15}{10}0.75^{10}(1-0.75)^{15-10}+\binom{15}{11}0.75^{11}(1-0.75)^{15-11}$

= $3003*0.75^{10} *0.25^{5} + 1365*0.75^{11} *0.25^{4}$ = 0.3903

(d) Probability that more than 10 of the problems can be resolved today is

given by = P(X > 10)

P(X > 10) = P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) + P(X = 15)

= $\binom{15}{11}0.75^{11}(1-0.75)^{15-11}+\binom{15}{12}0.75^{12}(1-0.75)^{15-12} + \binom{15}{13}0.75^{13}(1-0.75)^{15-13}+\binom{15}{14}0.75^{14}(1-0.75)^{15-14} + \binom{15}{15}0.75^{15}(1-0.75)^{15-15}$

= $1365*0.75^{11} *0.25^{4} + 455*0.75^{12} *0.25^{3}+105*0.75^{13} *0.25^{2} + 15*0.75^{14} *0.25^{1}+1*0.75^{15} *0.25^{0}$

= 0.6865

3 0

3 years ago

How do you find the question mark on #4?

kiruha [24]

64÷2 =32
90-32=58
58+58=116
360-116=244
?=244°

5 0

3 years ago

Find the Area of the figure

sineoko [7]

The figure is made up of two semi-circles and one triangle

--------------------------------
Find Radius
--------------------------------
Radius = Diameter ÷ 2
Radius = 5 ÷ 2
Radius = 2.5 ft

Area of the semi-circle = 1/2 πr²
Area of the semi-circle = 1/2 x π x (2.5)²
Area of the semi-circle = 9.82 ft²

Area of the triangle= 1/2 x base x height
Area of the triangle = 1/2 x 6 x 4
Area of the triangle = 12 ft²

Total area = 9.82 + 9.82 + 12
Total area = 31.63 ft²

--------------------------------------------
Total Area = 31.63 ft²
--------------------------------------------

4 0

3 years ago

Need answers quick its due in 1 hour!!!!!

antiseptic1488 [7]

Answer:

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i made a video explaining its on

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

A weight clinic recorded the weight lost (in pounds) by each client of a weight control clinic during the last year, and got the

borishaifa [10]

Answer:

Class interval ____, Frequency _ C/frequency

1 - 10 ____________ 1 _________ 1

11 - 20 ___________ 4 _________ 5

20 - 30 __________ 6 _________ 11

31 - 40 ___________3 _________ 14

41 - 50 ___________ 1 _________ 15

51 - 60 ___________ 1 _________ 16

Step-by-step explanation:

Given the data :

35, 26, 31, 17, 46, 30, 28, 21, 26, 34, 15, 27, 7, 18, 16, 57

Class interval ____, Frequency _ C/frequency

1 - 10 ____________ 1 _________ 1

11 - 20 ___________ 4 _________ 5

20 - 30 __________ 6 _________ 11

31 - 40 ___________3 _________ 14

41 - 50 ___________ 1 _________ 15

51 - 60 ___________ 1 _________ 16

The next to highest frequency group has a frequency of 4 and the highest frequency of 6

Total frequency, n = (1 + 4 + 6 + 3 + 1 + 1) = 16

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3 years ago