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pashok25 [27]
3 years ago
12

1. Which of the following is a correctly written thermochemical equation?

Chemistry
2 answers:
Harman [31]3 years ago
8 0
1. Which of the following is a correctly written thermochemical equation?C3H8 (g) + 5O2 (g) 3CO2 (g) + 4H2O (l), H = 2,220 kJ/mol

It is the answer because it shows everything needed to describe a reaction. It has the state and the heat of reaction.

2. How does a phase change affect a thermochemical equation?

It can affect the (delta) H value. It can either increase or decrease that value.

WITCHER [35]3 years ago
7 0

Explanation:

1. Thermochemical equation is balance stoichiometric chemical equation written with the phases of the reactants and products in the brackets along with the enthalpy change of the reaction.

The given correct thermochemical reactions are:

Fe(s)+O_2(g)\rightarrow Fe_2O_3(s),\Delta H = 3,926 kJ


C_3H_8(g)+5O_2 (g)\rightarrow 3CO_2 (g)+4H_2O(l),\Delta H= 2,220 kJ/mol

2. Phase change affect the value of the enthalpy change of the thermochemical equation. This is because change in phase is accompanied by change in energy. For example:

H_2O(s)\rightarrow H_2O(g),\Delta H_{s}=51.1 kJ/mol

H_2O(l)\rightarrow H_2O(g),\Delta H_{v}=40.65 kJ/mol

In both reaction phase of water is changing with change in energy of enthalpy of reaction.

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A typical adult human body contains approximately 2.500 L of blood plasma. How many grams of blood plasma are in the typical adu
kirill115 [55]

Answer:

m=2.575g

Explanation:

Hello,

In this case, since the density is defined as the ratio of the mass and volume:

\rho =\frac{m}{V}

We can compute the mass of blood as follows:

m=\rho *V=1.03g/L*2.500L\\\\m=2.575g

Best regards.

7 0
3 years ago
The change in internal energy for the combustion of 1.0 mol of octane at a pressure of 1.0 atm is -5084.1 kj . f the change in e
TEA [102]

<u>Given:</u>

Change in internal energy = ΔU = -5084.1 kJ

Change in enthalpy = ΔH = -5074.3 kJ

<u>To determine:</u>

The work done, W

<u>Explanation:</u>

Based on the first law of thermodynamics,

ΔH = ΔU + PΔV

the work done by a gas is given as:

W = -PΔV

Therefore:

ΔH = ΔU - W

W = ΔU-ΔH = -5084.1 -(-5074.3) = -9.8 kJ

Ans: Work done is -9.8 kJ


6 0
3 years ago
How many atoms of cobalt are in 4 moles of cobalt?
Anna [14]
<h3>Answer:</h3>

2 × 10²⁴ atoms Co

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

4 mol Co (Cobalt)

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

  1. Set up:                               \displaystyle 4 \ mol \ Co(\frac{6.022 \cdot 10^{23} \ atoms \ Co}{1 \ mol \ Co})
  2. Multiply/Divide:                 \displaystyle 2.4088 \cdot 10^{24} \ atoms \ Co

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 1 sig fig.</em>

2.4088 × 10²⁴ atoms Co ≈ 2 × 10²⁴ atoms Co

4 0
3 years ago
If 75.0 g of a liquid has a volume of 62.4 mL ,calculate the liquid’s density
Galina-37 [17]
<span>To calculate the density of a liquid, you have to first know that density is the amount of substance per unit of volume. In this specific question, density will be found with units of g/mL. Now, the density can be found by dividing the amount of liquid, 75.0g, by the volume, 62.4mL. Doing this we get: 75.0g/62.4mL= 1.2 g/mL as the density of the liquid.</span>
4 0
3 years ago
How many significant figures are in 120 miles?
balu736 [363]
2 significant zeros.

1 and 2 are the significant zeros.

pls mark brainliest
4 0
3 years ago
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