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pashok25 [27]
3 years ago
12

1. Which of the following is a correctly written thermochemical equation?

Chemistry
2 answers:
Harman [31]3 years ago
8 0
1. Which of the following is a correctly written thermochemical equation?C3H8 (g) + 5O2 (g) 3CO2 (g) + 4H2O (l), H = 2,220 kJ/mol

It is the answer because it shows everything needed to describe a reaction. It has the state and the heat of reaction.

2. How does a phase change affect a thermochemical equation?

It can affect the (delta) H value. It can either increase or decrease that value.

WITCHER [35]3 years ago
7 0

Explanation:

1. Thermochemical equation is balance stoichiometric chemical equation written with the phases of the reactants and products in the brackets along with the enthalpy change of the reaction.

The given correct thermochemical reactions are:

Fe(s)+O_2(g)\rightarrow Fe_2O_3(s),\Delta H = 3,926 kJ


C_3H_8(g)+5O_2 (g)\rightarrow 3CO_2 (g)+4H_2O(l),\Delta H= 2,220 kJ/mol

2. Phase change affect the value of the enthalpy change of the thermochemical equation. This is because change in phase is accompanied by change in energy. For example:

H_2O(s)\rightarrow H_2O(g),\Delta H_{s}=51.1 kJ/mol

H_2O(l)\rightarrow H_2O(g),\Delta H_{v}=40.65 kJ/mol

In both reaction phase of water is changing with change in energy of enthalpy of reaction.

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23.495 g sample of aqueous waste leaving a fertilizer manufacturer contains ammonia. The sample is diluted with 72.311 g of wate
Otrada [13]

Answer:

1.86% NH₃

Explanation:

The reaction that takes place is:

  • HCl(aq) + NH₃(aq) → NH₄Cl(aq)

We <u>calculate the moles of HCl that reacted</u>, using the volume used and the concentration:

  • 32.27 mL ⇒ 32.27/1000 = 0.03227 L
  • 0.1080 M * 0.03227 L = 3.4852x10⁻³ mol HCl

The moles of HCl are equal to the moles of NH₃, so now we <u>calculate the mass of NH₃ that was titrated</u>, using its molecular weight:

  • 3.4852x10⁻³ mol NH₃ * 17 g/mol = 0.0592 g NH₃

The weight percent NH₃ in the aliquot (and thus in the diluted sample) is:

  • 0.0592 / 12.949 * 100% = 0.4575%

Now we <u>calculate the total mass of NH₃ in the diluted sample</u>:

Diluted sample total mass = Aqueous waste Mass + Water mass = 23.495 + 72.311 = 95.806 g

  • 0.4575% * 95.806 g = 0.4383 g NH₃

Finally we calculate the weight percent NH₃ in the original sample of aqueous waste:

  • 0.4383 g NH₃ / 23.495 g * 100% = 1.86% NH₃

6 0
3 years ago
Which stage of cell division rusults in the formation of four new haploid cells
hichkok12 [17]
That would be telophase 2 of Meiosis
5 0
3 years ago
Give six examples of complex compounds.
ra1l [238]

Answer:

Examples of complex compound include potassium ferrocyanide K4[Fe(CN)6] and potassium ferricyanide K3[Fe(CN)6]. Other examples include pentaamine chloro cobalt(III) chloride [Co(NH)5Cl]Cl2 and dichlorobis platinum(IV) nitrate [Pt(en)2Cl2](NO3)2.

3 0
4 years ago
If you dilute 40.0 mL of a 7.0 M solution to make 100.0 mL of solution, what is the molarity of the dilute solution?
Burka [1]

Answer:

2.8M

Explanation:

The following data were obtained from the question:

Volume of stock solution (V1) = 40mL

Molarity of the stock solution (M1) = 7M

Volume of diluted solution (V2) = 100mL

Molarity of diluted solution (M2) =?

Using the dilution formula, we can easily find the molarity of the diluted solution as follow:

M1V1 = M2V2

7 x 40 = M2 x 100

Divide both side by 100

M2 = (7 x 40)/100

M2 = 2.8M

Therefore, the molarity of the diluted solution is 2.8M

3 0
3 years ago
Scientific notation is___
astraxan [27]
The answer for this question is:

B. Scientific notation is used to keep track of very small and very large numbers during mathematical calculations.
7 0
4 years ago
Read 2 more answers
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