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maw [93]
3 years ago
6

What similarities are there between Beta Radiation and Alpha Radiation

Chemistry
1 answer:
joja [24]3 years ago
5 0

The largest particle, Alpha, has the least penetrative power. Positive charge is carried by alpha particles. Two neutrons and two protons are bound together to form an alpha particle. The helium-4 nucleus was later identified as the alpha particle. Among the three types of radioactive emissions, alpha particles have the most mass. An alpha particle has approximately 8000 times the mass of a beta particle. The penetrative power of an alpha particle is reduced due to its large size.

Beta particles are negative-charged high-energy electrons or positrons. Beta particles have a higher penetrative power than alpha particles due to their smaller size.

Hope this helps and if it does, don't be afraid to give my answer a "Thanks" and maybe a Brainliest if it's correct?  

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How much heat is required to raise the temperature of 225 grams of ice from -26.8 °C to steam at 133 °C ?
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<h3>Answer:</h3>

150000 J

<h3>General Formulas and Concepts:</h3>

<u>Chemistry</u>

<u>Thermodynamics</u>

Specific Heat Formula: q = mcΔT

  • <em>q</em> is heat (in J)
  • <em>m</em> is mass (in g)
  • <em>c</em> is specific heat (in J/g °C)
  • ΔT is change in temperature (in °C or K)

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right
<h3>Explanation:</h3>

<u>Step 1: Define</u>

<em>Identify variables</em>

[Given] <em>m</em> = 225 g

[Given] <em>c</em> = 4.184 J/g °C

[Given] ΔT = 133 °C - -26.8 °C = 159.8 °C

[Solve] <em>q</em>

<u>Step 2: Solve for </u><em><u>q</u></em>

  1. Substitute in variables [Specific Heat Formula]:                                          q = (225 g)(4.184 J/g °C)(159.8 °C)
  2. Multiply:                                                                                                           q = (941.4 J/°C)(159.8 °C)
  3. Multiply:                                                                                                           q = 150436 J

<u>Step 3: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

150436 J ≈ 150000 J

Topic: AP Chemistry

Unit: Thermodynamics

Book: Pearson AP Chemistry

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