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Monica [59]
3 years ago
12

Tammy spent of her savings on a watch. She then spent-of

Chemistry
1 answer:
zmey [24]3 years ago
5 0

Answer:

1 / 2 of her money would be left

Explanation:

<em>Tammy spent 2/5 of her savings on a watch. She then spent 1/6 of the remainder on a bag. What fraction of her money did she have left?</em>

<em />

Taking the question bits by bit;

<em>Tammy spent 2/5 of her savings on a watch</em>

Amount Spent = 2/5

Remainder = 1 - 2/5 = 3/5

<em>She then spent 1/6 of the remainder on a bag</em>

Amount Spent = 1/6  *  3/5 = 1/2  *  1/5  = 1 /10

Total amount spent = 2/5 + 1 /10 =   (4 + 1 ) / 10 = 5 / 10 = 1 / 2

Amount left = 1 - 1 /2 = 1 / 2

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Answer:

See below.

Explanation:

Because copper is a very good conductor of electricity so it will likely conduct any electricity away from the person.

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3 years ago
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chemical weathering_______ A.is caused by freezing B.breaks apart rocks by physical process C.occurs when chemical reactions dis
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I believe that the answer is C.
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4 years ago
Please somebody help I have no idea what the correct answer is! (iii) and (iv)
brilliants [131]
Since phosphoric acid is H3PO4, which is known from PO4, with a charge of 3- so 3 hydrogen would balance it out, and sodium hydroxide is NaOH, it can be assumed that it results in H3(OH)3 + Na3PO4.
3 0
4 years ago
Calculate the number of formula units in 2.50 mol NaNO
marta [7]

The number of formula units in 2.50 mol of the compound is  15.1 * 10^23.

The question is unclear whether NaNO2 or NaNO3 is implied. However,in either case, the solution applies equally.

6.02 * 10^23 formula units of the compound are contained in 1 mole

x formula units are contained in 2.5 moles of the compound

x = 6.02 * 10^23 formula units * 2.5 moles/ 1 mole

x = 15.1 * 10^23 formula units of the compound.

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3 0
3 years ago
Tungsten (W) and chlorine (Cl) form a series of compounds with the following compositions:_______.
deff fn [24]

Answer:

WCl₂, WCl₄, WCl₅, WCl₆

Explanation:

Molar Mass of Tungsten = 184 g/mol

Mass of Chlorine = 35.5 g/mol

In the first compound;

Percentage of tungsten = 72.17 %

Upon solving;

72.17 % = 184

100 % = Total mass

Total mass of compound = 254.95g

Mass of chlorine = 254.95 - 184 = 70.95 (Dividing by 35.35; This is approximately 2 Chlorine atoms.

The Formular is WCl₂

In the second compound;

Percentage of tungsten = 56.45 %

Upon solving;

56.45 % = 184

100 % = Total mass

Total mass of compound = 325.95 g

Mass of chlorine = 325.95 - 184 = 141.95g (Dividing by 35.35; This is approximately 4 Chlorine atoms.

The Formular is WCl₄

In the third compound;

Percentage of tungsten = 50.91 %

Upon solving;

50.91 % = 184

100 % = Total mass

Total mass of compound = 361.42 g

Mass of chlorine =  361.42 - 184 = 177.42 (Dividing by 35.35; This is approximately 5 Chlorine atoms.

The Formular is WCl₅

In the fourth compound;

Percentage of tungsten = 46.39 %

Upon solving;

46.39 % = 184

100 % = Total mass

Total mass of compound = 396.64 g

Mass of chlorine = 396.64 - 184 = 212.64 (Dividing by 35.35; This is approximately 6 Chlorine atoms.

The Formular is WCl₆

4 0
3 years ago
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