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Montano1993 [528]
3 years ago
14

Given that f(x) =3x^2 - 6x + 11 ,find the values of a,b and c for which f(x) = a(x - b)^2 + c

Mathematics
1 answer:
V125BC [204]3 years ago
3 0
First you have to complete the square. The first step would be 3x^2-6x=-11. Then you divide -6 by 2 and square the number you get. 3x^2-6x+9=-11+9. 3x^2-6x+9=-2. Factor out the three to get 3(x^2-2x+3)=-2. You can't factor what is in the parenthesis. You should then add two to each side. 3(x^2-2x+3)+2.A = 3B= I don't knowC = 2
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Answer:

y=2x^2-\frac{4}{3}x-\frac{10}{3}

Step-by-step explanation:

we know that

The roots of the quadratic function (x-intercepts) are

x=-1 and x=5/3

so

we can write the equation of the parabola as

y=a(x+1)(x-\frac{5}{3})

where

a is a coefficient

Remember that

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substitute the value of x and the value of y of the ordered pair in the quadratic equation and solve for a

x=5, y=40

40=a(5+1)(5-\frac{5}{3})

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y=2(x+1)(x-\frac{5}{3})

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see the attached figure to better understand the problem

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