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JulsSmile [24]
3 years ago
11

1. What is the most precise name for quadrilateral ABCD with vertices A(-2,4), B(5,6), C(12,4), and D(5,2)?

Mathematics
2 answers:
zaharov [31]3 years ago
7 0
The first one is B because of the first attachment. The second one is A because of the second attachment. The third one is C because of the expression used to solve for sum of angles: 
(n-2)180 
(8-2)180
1080
Hope this helps!

lys-0071 [83]3 years ago
5 0

Answer:

1) b

2)a

3)b

Step-by-step explanation:

1)Consider AC and BD. Both have common mid point as (5,4) and (5,4)

Hence diagonals bisect each other. Slope of AC=0 and slope of BD = -4/0

i.e. one is horizontal and other is vertical. Hence diagonals bisect at right angles.  So rhombus.

2) ABCD has adjacent sides equal and diagonals bisect each other at right angles.

Slope of AC =1 and BD =-1 that is product =-1. Kites are perpendicular.

So kite

3) Any polygon irrespective of number of sides, the exterior angles will add upto 360 degrees.

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Factorise:<br> 8 x 3 + 729 +10800² + 486X.
hjlf

Answer:

(2x+9)  ^3

Step-by-step explanation:

 (((8 • (x3)) +  729) +  (22•33x2)) +  486x

 ((23x3 +  729) +  (22•33x2)) +  486x

Factoring:  8x3+108x2+486x+729  

 8x3+108x2+486x+729  is a perfect cube which means it is the cube of another polynomial  

 In our case, the cubic root of  8x3+108x2+486x+729  is  2x+9  

 Factorization is  (2x+9)3

Hope this helped

8 0
3 years ago
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I think the root of "3x + 1 = 7" is 2...

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Answer:

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Step-by-step explanation:

6 0
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