Answer:
![\large\boxed{x\leq-27}](https://tex.z-dn.net/?f=%5Clarge%5Cboxed%7Bx%5Cleq-27%7D)
Step-by-step explanation:
![\dfrac{x}{-9}\geq3\qquad\text{change the signs}\\\\\dfrac{x}{9}\leq-3\qquad\text{multiply both sides by 9}\\\\9\!\!\!\!\diagup^1\cdot\dfrac{x}{9\!\!\!\!\diagup_1}\leq(-3)(9)\\\\x\leq-27](https://tex.z-dn.net/?f=%5Cdfrac%7Bx%7D%7B-9%7D%5Cgeq3%5Cqquad%5Ctext%7Bchange%20the%20signs%7D%5C%5C%5C%5C%5Cdfrac%7Bx%7D%7B9%7D%5Cleq-3%5Cqquad%5Ctext%7Bmultiply%20both%20sides%20by%209%7D%5C%5C%5C%5C9%5C%21%5C%21%5C%21%5C%21%5Cdiagup%5E1%5Ccdot%5Cdfrac%7Bx%7D%7B9%5C%21%5C%21%5C%21%5C%21%5Cdiagup_1%7D%5Cleq%28-3%29%289%29%5C%5C%5C%5Cx%5Cleq-27)
8+11 is 19
Hope it helped
Alright, so first we need to establish two things.
First, the compliment of a set is like the extreme opposite; everything that is not in set B will be in the complement.
Second, we need to find out what B is.
Okay, so B is everything that is greater than 2, that's given. That includes 3, 4, and 5. B = {3, 4, 5}. There are three items in this set.
The numbers that aren't included are 1 and 2. The complement of B, let's call this C I guess, is C = {1, 2}. There are 2 items in this set.
The answer, I believe, is <em>two</em>. Hope this helps!
Answer:
option d is correct answer