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Ulleksa [173]
3 years ago
6

Sasha is making some shelves which are 75.5 cm long. If the wood she is using is 180 cm long, how many pieces will she need to m

ake six shelves?
Mathematics
1 answer:
anzhelika [568]3 years ago
6 0

Answer:

3

Step-by-step explanation:

Since the shelves are 75.5cm long, the total length she would be needing is 75.5cm × 6 = 453cm

Now, the length of the wood she is using is 180cm, to get enough length to make the shelves, we would need to divide 453cm by 180cm which gives a value of around 2.51

This is approximately equal to 3 when rounded up to the nearest whole number.

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<span>Factor 80t - 16t = 0
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If x = 3(y+w)– 1, what is the value of w in terms of x and y?
bixtya [17]
The answer for that is the second one
7 0
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Train A leaves the station traveling east at 50 mph while train B leaves the station 30 minutes later traveling west at 65 mph.
stepladder [879]

Answer:

Change 45 min to .75 hrs

Distance = speed * time

Train A's distance = 55(t+.75)

Train B's distance = 70t

The equation

D(t) = 70t + 55(t+.75)

8 0
2 years ago
Find the range of the following piecewise function.
mash [69]

Answer:

\huge\boxed{[-5;\ -2)\ \cup\ [3;\ 13)}

Step-by-step explanation:

The following piecewise functions are linear functions. The graph of any of them is a line segment.

We just need to calculate the value of the function at each end specified in the brace.

y=3x-2\ \text{if}\ -1\leq x

Substitute x =-1 and x = 0:

x=-1\\y=3(-1)-2=-3-2=-5\\\\x=0\\y=3(0)-2=0-2=-2

Range of this piece is [-5; -2)

y=2x+3\ \text{if}\ 0\leq x

Substitute x =0and x = 5:

x=0\\y=2(0)+3=0+3=3\\\\x=5\\y=2(5)+3=10+3=13

Range of this piece is [3; 13)

Therefore the range of the following piecewise function is:

[-5;\ -2)\ \cup\ [3;\ 13)

Look at the picture.

6 0
3 years ago
The probability that a student has a Visa card (event V) is .63. The probability that a student has a MasterCard (event M) is .1
Aleksandr-060686 [28]

Answer:

a)  The probability that a student has either a Visa card or a MasterCard is 0.71.  

b) V and M are not independent.

Step-by-step explanation:

Given : The probability that a student has a Visa card (event V) is 0.63. The probability that a student has a MasterCard (event M) is 0.11. The probability that a student has both cards is 0.03.

To find :

a) The probability that a student has either a Visa card or a MasterCard ?

b)  In this problem, are V and M independent ?

Solution :

The probability that a student has a visa card(event V) is P(V)= 0.63

The probability that a student has a MasterCard (event M) is P(M)= 0.11

The probability that a student has both cards  is P(V \cap M)=0.03

a) Probability that a student has either a Visa card or a Master Card is given by,

P(V \cup M) = P(V) + P(M) - P(V\cap M)

P(V \cup M) = 0.63+ 0.11- 0.03

P(V \cup M) =0.74- 0.03

P(V \cup M) =0.71

The probability that a student has either a Visa card or a MasterCard is 0.71.

b) Two events, A and B, are independent if P(A\cap B)=P(A)P(B)

For V and M to be independent the condition is satisfied,

P(V\cap M)=P(V)P(M)

Substitute the values,

0.03=0.63\times 0.11

0.03\neq 0.0693

So, V and M are not independent.

6 0
3 years ago
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