The ball may attracted to the magnet.
<h3>How can we understand that the hanging ball will be attracted to the magnet or not?</h3>
- From the question, we understand that the ball is attracted by the north pole of the bar magnet, then the bar magnet flipped over and the south pole is brought near the hanging ball.
- As we know, in this type of experiments of bar magnet most of the times the ball is made out of steel.
- Steel is a magnetic material.
- Magnetic materials gets attracted to the magnet at both the North and South pole.
- This can be compared to how neutral objects also gets attracted to the positively and negatively charged rods through the Polarization force.
So, If the bar magnet is flipped over and the south pole is brought near the hanging ball, The ball will be attracted to the magnet.
Learn more about the bar magnet:
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Answer: Fourth option. It increased by a factor of 3.
Solution:
m1=1.0 kg
Cylinder's gravitational potential energy: Ep=m*g*h
Ep1=(1.0 kg)*g*h
Ep1=g*h
m2=3.0 kg
Ep2=(3.0 kg)*g*h
Ep2=3*g*h
Replacing g*h by Ep1 in the equation above:
Ep2=3*Ep1
Then, the cylinder's gravitational potential energy increased by a factor of 3.
The potential energy of the model will be the greatest at point C while it will be the least at point E. Option B and D are correct.
<h3>
What is potential energy?</h3>
The potential energy of an object is due to its position. It can be given as the formula,
Where,
- potential energy
- mass
- gravitation acceleration
- height
From the formula since the mass and gravitation acceleration is constant, the potential energy of the model will depend upon the height only.
The potential energy will be greatest at point C because the relative position of the ball is the highest from the earth.
The potential energy will be lowest at point E because the height of the ball is the least in this position.
Therefore, the potential energy of the model will be the greatest at point C while it will be the least at point E.
Learn more about kinetic energy:
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To solve the exercise it is necessary to apply the concepts of Mangenetic Force and Energy generated by electric potential.
By definition we know that the energy within an electron through voltage can be expressed as
Where,
e= charge of electron
V= Voltage
The kinetic energy of a moving system can be expressed as
Where,
m = mass
v = Velocity
For energy conservation we have to
Solving to find v,
On the other hand we have that the Magnetic Force can be expressed as,
Where,
q=charge of proton
v=velocity
B= Magnetic field
Angle between the magnetic field and the velocity vector (It is perpendicular in this case)
Using the previous equation from velocity in the Force equation we have,
PART A) Replacing the values to find the force we have,
Answer:
11,627.91 kg/m^3
Explanation:
The computation of the density of the material is shown below
Given that
Mass , m = 1 kg
Height, H - 47 mm = 0.047 m
Diameter, d = 49 mm = 0.049 m
Now radius, r = D ÷ 2
= 0.049 ÷ 2
= 0.0245
Volume = πr^2h
= 3.14 × (0.0245)^2 × 0.047
= 0.000086m^3
Now the density of the material is
= mass ÷ volume
= 1÷ 0.000086m^3
= 11,627.91 kg/m^3
