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3 years ago

DNA is coiled into chromosomes in a cell's

2 answers:

8 0

In the nucleus of each cell, the DNA molecule is packaged into thread-like structures called chromosomes. Each chromosome is made up of DNA tightlycoiled many times around proteins called histones that support its structure

tia_tia [17]3 years ago

6 0

Answer: Cell's nucleus

Explanation :

The full form of DNA is Deoxyribonucleic acid. The genetic information of a cell is organized in the DNA. It is inherited from parents by their children.

DNA is coiled into chromosomes in a cell's nucleus. It has a shape like a double helix. It is twisted in the form of spirals.

Hence, DNA is coiled into chromosomes in a cell's Nucleus.

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For work to be accomplished we must have

Nat2105 [25]

The answer they are looking for is the last one. However the last two are technically correct but the third one would result in negative work.

8 0

3 years ago

Read 2 more answers

At t = 0, Ball 1 is dropped from the top of a 22 m-high building. At the same instant Ball 2 is thrown straight up from the base

Crazy boy [7]

Answer:

The two balls pass each other at a height of 5.53 m

vf1=17.97 m/s

vf2=-5.96 m/s

Explanation:

Vertical Motion

An object thrown from the ground at speed vo, is at a height y given by:

$y=vo.t-g.t^2/2$

Where t is the time and $g=9.8\ m/s^2$

Furthermore, an object dropped from a certain height h will fall a distance y, given by:

$y=g.t^2/2$

Thus, the height of this object above the ground is:

$H = h-g.t^2/2$

The question describes that ball 1 is dropped from a height of h=22 m. At the same time, ball 2 is thrown straight up with vo=12 m/s.

We want to find at what height both balls coincide. We'll do it by finding the time when it happens. We have written the equations for the height of both balls, we only have to equate them:

$vo.t-g.t^2/2=h-g.t^2/2$

Simplifying:

$vo.t=h$

Solving for t:

$t=h/vo=22/12=1.833\ s$

The height of ball 1 is:

$H = 22-9.8.(1.833)^2/2$

H = 5.53 m

The height of ball 2 is:

$y=12\cdot(1.833)-9.8\cdot(1.833)^2/2$

y=5.53 m

As required, both heights are the same.

The speed of the first ball is:

$vf1=g.t=9.8\cdot 1.833=17.97\ m/s$

vf1=17.97 m/s

The speed of the second ball is:

$vf2=vo-gt=12-9.8\cdot 1.833=-5.96\ m/s$

vf2=-5.96 m/s

This means the second ball is returning to the ground when both balls meet

3 0

3 years ago

A container of gas is at a pressure of 3.7 x 10^5 Pa. How much work is done by the gas if its volume expands by 1.6 m^3 ?

Dmitriy789 [7]

Answer:

592000 J

Explanation:

We'll begin by converting 3.7×10⁵ Pa to Kg/ms². This can be obtained as follow:

1 Pa = 1 Kg/ms²

Therefore,

3.7×10⁵ Pa = 3.7×10⁵ Kg/ms²

Next, we shall determine the workdone.

Workdone is given by the following equation:

Workdone (Wd) = pressure (P) × change in volume (ΔV)

Wd = PΔV

With the above formula, the work done can be obtained as follow:

Pressure (P) = 3.7×10⁵ Kg/ms²

Change in volume (ΔV) = 1.6 m³

Workdone (Wd) =?

Wd = PΔV

Wd = 3.7×10⁵ × 1.6

Wd = 592000 Kgm²/s²

Finally, we shall convert 592000 Kgm²/s² to Joule (J). This can be obtained as follow:

1 Kgm²/s² = 1 J

Therefore,

592000 Kgm²/s² = 592000 J

Therefore, the Workdone is 592000 J.

6 0

3 years ago

A girl swings a 0.250 kg rock attached to a taut string in a circle around her head. Her hand holds the end of the string above

nydimaria [60]

Complete Question

The diagram of with this question is shown on the first uploaded image

Answer:

The value is $v = -6.543 \^ i + 9.47 \^ j + 0 \^ k$

Explanation:

From the question we are told that

The mass of the rock is $m = 0.250 \ kg$

The length of the string is $L = 0.75 \ m$

The angle the string makes horizontal is $\theta = 11.9^o$

The angle which the projection of the string onto the xy -plane makes with the positive x-axis is $\phi = 34.6^o$

The angular velocity of the rock is $w = 2.50 rev/s = 2.50 * 2\pi =15.7 \ rad/s$

Generally the radius of the circle made by the length of the string is mathematically represented as

$r = L cos(\theta )$

=> $r = 0.75 cos(11.9 )$

=> $r = 0.734 \ m$

Generally the resultant tangential velocity is mathematically represented as

$v__{R}} = w * r$

=> $v__{R}} = 15.7 *0.734$

=> $v__{R}} = 11.5 \ m/s$

Generally the tangential velocity along the x-axis is

$v_x = -v__{R}} * sin(\phi)$

=> $v_x =- 11.5 * sin(34.6)$

=> $v_x = -6.543 \ m/s$

The negative sign show that the velocity is directed toward the negative x-axis

Generally the tangential velocity along the y-axis is

$v_y = v__{R}} * cos(\phi)$

=> $v_y = 11.5 * cos(34.6)$

=> $v_y = 9.47 \ m/s$

Generally the tangential velocity along the y-axis is

$v_z = v__{R}} * cos(90)$

=> $v_z = 0 \ m/s$

Generally the tangential velocity at that instant is mathematically represented as

$v = -6.543 \^ i + 9.47 \^ j + 0 \^ k$

8 0

3 years ago

an NHL hockey player (m=90 kg) stands motionless on the ice . the 10 kg stanley cup is thrown to the player at 4m/s. after he ca

spayn [35]

Answer:v=0.4 m/s

Explanation:

Mass hockey player $m_1=90 kg$

mass of cup $m_2=10 kg$

Velocity of cup $u=4 m/s$

let v be the velocity of the combined system

Conserving momentum

$m_1\cdot 0+m_2u=(m_1+m_2)v$

$v=\frac{10\times 4}{100}$

$v=\frac{40}{100}$

$v=0.4 m/s$

4 0

3 years ago