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victus00 [196]
2 years ago
9

What can i do to recycle?

Physics
1 answer:
mafiozo [28]2 years ago
8 0

Answer:

You could throw away the following items:

Mixed paper: Newspaper, magazine, junk mail, cardboard, frozen food packaging, wrapping paper, paper bags, etc.

Cans: aluminum, foil, tin, steal, aerosol (empty without pressure) and metal food trays. ...

Unbroken glass: Wine bottles, bottles and jars.

Plastic: Rigid containers like milk jugs, shampoo or water bottles.

Hope this helped

You might be interested in
2. The substances that undergo change in a chemical reaction are called
AVprozaik [17]
Reactants

In a chemical reaction, the substances that undergo change are called reactants. The new substances formed as a result of that change are called products.
4 0
3 years ago
A person looking out the window of a stationary train notices that raindrops are falling vertically down at a speed of 3.84 m/s
JulijaS [17]

Answer:

the train is moving at the speed of v = 1.79 m/s

Explanation:

given,

rain drop is falling vertically down with the speed of  = 3.84 m/s

angle of the rain drop = 25°                      

tan θ = \dfrac{v}{u}                      

tan 25° = \dfrac{v}{3.84}                      

v =3.84 × tan 25°                      

v = 1.79 m/s                  

hence, the train is moving at the speed of v = 1.79 m/s

3 0
3 years ago
A boy standing on the bridge kicks a stone into the water below. He kicks the stone with a horizontal velocity of 8.06 m/s. It l
Ronch [10]

Time taken to reach water :

t = \dfrac{D}{v}\\\\t=\dfrac{6.78}{8.06}\ s\\\\t=0.84\ s

Now, initial vertical speed , u = 0 m/s.

By equation of motion :

h = ut +\dfrac{at^2}{2}

Here, a = g = acceleration due to gravity = 9.8 m/s².

So,

h = 0(t) +\dfrac{9.8\times 0.84^2}{2}\\\\h=3.46\ m

Therefore, the height of the bridge is 3.46 m.

Hence, this is the required solution.

6 0
3 years ago
A uniform disk of mass M = 4.9 kg has a radius of 0.12 m and is pivoted so that it rotates freely about its axis. A string wrapp
AlekseyPX

Answer:

(A) 2.4 N-m

(B) 0.035kgm^2

(C) 315.426 rad/sec

(D) 1741.13 J

(E) 725.481 rad

Explanation:

We have given mass of the disk m = 4.9 kg

Radius r = 0.12 m, that is distance = 0.12 m

Force F = 20 N

(a) Torque is equal to product of force and distance

So torque \tau =Fr, here F is force and r is distance

So \tau =20\times 0.12=2.4Nm

(B) Moment of inertia is equal to I=\frac{1}{2}mr^2

So I=\frac{1}{2}\times 4.9\times 0.12^2=0.035kgm^2

Torque is equal to \tau =I\alpha

So angular acceleration \alpha =\frac{\tau }{I}=\frac{2.4}{0.035}=68.571rad/sec^2

(C) As the disk starts from rest

So initial angular speed \omega _{0}=0rad/sec

Time t = 4.6 sec

From first equation of motion we know that \omega =\omega _0+\alpha t

So \omega =0+68.571\times  4.6=315.426rad/sec

(D) Kinetic energy is equal to KE=\frac{1}{2}I\omega ^2=\frac{1}{2}\times 0.035\times 315.426^2=1741.13J

(E) From second equation of motion

\Theta =\omega _0t+\frac{1}{2}\alpha t^2=0\times 4.6+\frac{1}{2}\times 68.571\times 4.6^2=725.481rad

3 0
3 years ago
What is the differential equation governing the growth of current in the circuit as a function of time after t=0? express the ri
Reika [66]

Answer:

v_{b}=ir+L\frac{di}{dt}

Explanation:

A differential equation that contain a term with di(t)/dt is in a RL circuit. Here we have

v_{b}=v_{r}+v_{i}

where vr is the voltage in the resistance, vi is the voltage in the inductance and vb is the source voltage. But also we have that

v_{r}=ir\\v_{i}=L\frac{di}{dt}

where L is the inductance of the circuit, r is the resistance an i is the current. By replacing we have the differential equation

v_{b}=ir+L\frac{di}{dt}

I hope this is useful for you

regards

3 0
3 years ago
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