Is a piece of hardware that carries out the instructions of a computer program. It performs the basic arithmetical, logical, and input/output operations of a computer system.
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Answer:
SQL queries
The command used to display the customer ID and total number of orders placed is given below
Query:
SELECT CustomerID, COUNT (orderID) AS TotalOrders
FROM Order_Table
GROUP BY CustomerID
Explanation:
SQL queries
The command used to display the customer ID and total number of orders placed is given below
Query:
SELECT CustomerID, COUNT (orderID) AS TotalOrders
FROM Order_Table
GROUP BY CustomerID
SELECT - To query the database and get back the specified fields SQL uses the select statement
CustomerID is a coloumn name
The function COUNT(OrderID) returns the number of orders
Totalorderds is a label
FROM - To query the database and get back the preferred information by specifying the table name
Order_Table is a table name
GROUP BY - The clause is used to group the result of a SELECT statement done on a table where the tuple values are similar for more than one column
The table below displays the CustomerID and total number of orders placed
CustomerID Totalorders
4 28
1 6
12 5
16 5
6 3
9 3
15 3
3 1
13 1
14 1
The table below shows the total number of orders situated for each sales person
SalesPerson_ID TotalOrders
3 16
2 3
4 3
5 3
August 10, 1932 in Billund, Denmark
Answer: Multi-user issue
Explanation: A database management system scheme can have multi-user issue when the designing of the system is not made properly. The multi user issue rises when the users concurrently access the data from the database and related error get invoked due to some reason like repeatable reading issue, serialization, etc.
The reading problem is usually can be related to reading of the database in uncommitted manner, uncommitted reading, repeatedly reading etc.Thus, Cora and Owen are accessing the database concurrently which can create multi-user issue.
Answer:
In C++:
#include <iostream>
using namespace std;
int main(){
string fname,lname; int num;
cout<<"Firstname: "; cin>>fname;
cout<<"Lastname: "; cin>>lname;
cout<<"4 digits: "; cin>>num;
string login = lname;
if(lname.length()>=5){
login = lname.substr(0, 5); }
login+=fname.substr(0,1)+to_string(num%100);
cout<<login;
return 0;
}
Explanation:
See attachment for explanation where I used comments to explain each line
