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Alex_Xolod [135]
3 years ago
7

Which could be the missing first term of the expression that , when fully simplified would be a binomial with a degree of 4 sele

ct three options -5xy2 + 9x2y
Mathematics
1 answer:
notka56 [123]3 years ago
3 0

Answer:

Step-by-step explanation:

I can only solve for – 5xy3 + 9x2y

If 0 is the first term, upon simplifying this term would disappear and leave:

-5xy³+9x²y.

The degree of a binomial is found by finding the degree of each monomial and taking the largest one. 

The degree of each monomial is found by adding the exponents of the variables; for -5xy³, the degree would be 1+3=4; for 9x²y, it would be 2+1=3.  The highest is 4, so the degree of the polynomial is 4.

If 9x²y is the first term, to simplify we would combine like terms.  9x²y + 9x²y would be the like terms, and would give us 18x²y; this makes the simplified polynomial 

-5xy³ + 9x²y. 

The degree of the first monomial is 1+3=4; the degree of the second monomial is 2+1=3.  The highest is 4, so the degree of the polynomial is 4.

If 4xy³ is added, we simplify by combining like terms.  4xy³ - 5xy³ are the like terms, and give us -1xy³.  

This gives us the polynomial: -1xy³ + 9xy²

The degree of the first monomial is 1+3=4; the degree of the second monomial is 1+2=3.  

The highest is 4, so the degree of the polynomial is 4.

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Answer:

Step-by-step explanation:

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4 years ago
Which number is halfway between 1/2 and 2/3 ?
MariettaO [177]
For example, 3/5.

3/5 = 0.6.

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8 0
4 years ago
If w÷3=3(w-1)-1 find the value of w<br><br>​
Licemer1 [7]

Answer:

3/2

Step-by-step explanation:

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5 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B216%5C%5C%7D" id="TexFormula1" title="\sqrt[3]{216\\}" alt="\sqrt[3]{216\\}"
aivan3 [116]

Answer:

6

Step-by-step explanation:

\sqrt[3]{216} = \sqrt[3]{8} · \sqrt[3]{27}  =  \sqrt[3]{2}³ · \sqrt[3]{3}³ = 2 x 3  = 6

7 0
3 years ago
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