PLEASE HELP WITH THIS ONE QUESTION

Write a blue print of a room a blueprint of a room drawn in a coordinate plane, using an appropriate scale – (out of 4)

svetoff [14.1K]

What your going to want to do is take graph paper each square is five feet draw whatever shape your room is on it and take perimeter and area I cant write the reflection as I don't know what room you have drawn.

8 0

3 years ago

Dylan and three of his friends went to dinner at Texas Roadhouse. The cost of the meal was $41.56. If they split the bill equall

Volgvan

Each person would pay 10.39 a piece

5 0

3 years ago

A piece of tile is 4 1/2 inches long and 3 1/4 inches wide. What is the area of the tile? A.7 3/4 B.12 C.12 1/8 D.14 5/8

Komok [63]

4 x 2 over 2

8/2 + 1/2 = 9/2

3 x 4 over 4

12/4 +1/4 = 13/4

Top times top over bottom times bottom.

9 x 13 over 2 x 4

117 / 8

14 and 5/8

7 0

3 years ago

I need help on 17 and 23 pls

ludmilkaskok [199]

Question # 17 Solution

Answer:

$x_{1}= \frac{mx_{2}-y_{2}+y_{1}}{m}$

Step-by-step Explanation:

The given expression

$m = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

And we have to solve for x₁

So,

Lets solve for x₁.

$m = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

Multiply both sides by x₂ - x₁

$m(x_{2}-x_{1})= (x_{2}-x_{1})\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

$m(x_{2}-x_{1})= (y_{2}-y_{1})$

$mx_{2}-mx_{1}= (y_{2}-y_{1})$

$-mx_{1}= y_{2}-y_{1}-mx_{2}$

Divide both sides by -m

$\frac{-mx_{1}}{-m}= \frac{y_{2}-y_{1}-mx_{2}}{-m}$

$x_{1}= \frac{mx_{2}-y_{2}+y_{1}}{m}$

Therefore, $x_{1}= \frac{mx_{2}-y_{2}+y_{1}}{m}$

Question # 23 Solution

Answer:

$n= \frac{bx}{-b + x}$

Step-by-step Explanation:

The given expression

$\frac{nx}{b}-x=x$

And we have to solve for n

So,

Let's solve for n.

$\frac{nx}{b}-x=x$

Multiply both sides by b.

$-bn + nx = bx$

Factor out n.

$n(-b + x)= bx$

Divide both sides by -b + x.

$\frac{n(-b + x)}{-b + x}= \frac{bx}{-b + x}$

$n= \frac{bx}{-b + x}$

Therefore, $n= \frac{bx}{-b + x}$

Keywords: solution, equation

Learn more about the solution of equations from brainly.com/question/12864981

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6 0

4 years ago

Item 20 A rectangular school banner has a length of 54 inches and a width of 36 inches. A sign is made that is similar to the sc

siniylev [52]

Answer:

The ratio of the area of the school banner to the area of the sign is 1944 cubic inches : 192.61 cubic inches.

Step-by-step explanation:

Given:

A rectangular school banner has a length of 54 inches and a width of 36 inches. A sign is made that is similar to the school banner and has a length of 17 inches.

Now, to find the ratio of the area of the school banner to the area of the sign.

Dimensions of school banner :

Length = 54 inches.

Width = 36 inches.

Dimension of school sign:

Length = 17 inches.

So, to we find the width of sign by using cross multiplication method:

Let the width be $x.$