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ANEK [815]
3 years ago
13

If an element has 10 protons and 11 neutrons and 10 electrons, which expression correctly identifies the element?

Chemistry
1 answer:
Sunny_sXe [5.5K]3 years ago
6 0
When the number of protons and electrons are equal, that means the element is neutral. So, to know the element, find the element with an atomic number of 10. That would be Neon. Next, solve the mass number.

Mass number = protons +neutrons = 10+11 = 21

Thus, the expression should be written as shown in the attached picture.

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Explanation:

Because these unhardened glues are flammable, do not dispose of them in the trash or down the drain. Keep them away from open flames. If the glue is water-based, solidify it and throw it in the trash.

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4 years ago
WHAT HAPPENS WHEN AN ATOM LOSES AN ELECTRON TO ANOTHER ATOM?
cluponka [151]
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Read 2 more answers
Enthalpy of <br><br> CH4(g) + 2NO2(g) -&gt; N2(g) + CO2(g) + 2H2O(l)
stira [4]

Answer:

-177.9 kJ.

Explanation:

Use Hess's law. Ca(s) + CO2(g) + 1/2O2(g) → CaCO3(s) ΔH = -812.8 kJ 2Ca(s) + O2(g) → 2CaO(s) ΔH = -1269.8 kJ We need to get rid of the Ca and O2 in the equations, so we need to change the equations so that they're on both sides so they "cancel" out, similar to a system of equations. I changed the second equation. Ca(s) + CO2(g) + 1/2O2(g) → CaCO3(s) ΔH = -812.8 kJ 2CaO(s) → 2Ca(s) + O2(g) ΔH = +1269.8 kJ The sign changes in the second equation above since the reaction changed direction. Next, we need to multiply the first equation by two in order to get the coefficients of the Ca and O2 to match those in the second equation. We also multiply the enthalpy of the first equation by 2. 2Ca(s) + 2CO2(g) + O2(g) → 2CaCO3(s) ΔH = -1625.6 kJ 2CaO(s) → 2Ca(s) + O2(g) ΔH = +1269.8 kJ Now we add the two equations. The O2 and 2Ca "cancel" since they're on opposite sides of the arrow. Think of it more mathematically. We add the two enthalpies and get 2CaO(s) + 2CO2(g) → 2CaCO3(s) and ΔH = -355.8 kJ. Finally divide by two to get the given equation: CaO(s) + CO2(g) → CaCO3(s) and ΔH = -177.9 kJ.

5 0
3 years ago
The metal zirconium becomes superconducting at temperatures below 3.4000K.
dybincka [34]

Answer:

-269.75 degrees Celsius

Explanation:

7 0
3 years ago
How many moles are in 325mL of 1.25M (NH4)2SO4
mote1985 [20]

Answer:

n_{solute}=0.406mol(NH_4)_2SO_4

Explanation:

Hello,

In this case, since the molarity is defined as the ratio of the moles of the solute to the volume of the solution in liters:

M=\frac{n_{solute}}{V_{solution}}

For the given volume and molarity, we solve for the moles of ammonium sulfate (solute) as shown below:

n_{solute}=M*V_{solution}=1.25\frac{mol}{L}*325mL*\frac{1L}{1000mL}  \\\\n_{solute}=0.406mol(NH_4)_2SO_4

Best regards.

4 0
4 years ago
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