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3 years ago

How many moles are in 325mL of 1.25M (NH4)2SO4

Chemistry

1 answer:

mote1985 [20]3 years ago

4 0

Answer:

$n_{solute}=0.406mol(NH_4)_2SO_4$

Explanation:

Hello,

In this case, since the molarity is defined as the ratio of the moles of the solute to the volume of the solution in liters:

$M=\frac{n_{solute}}{V_{solution}}$

For the given volume and molarity, we solve for the moles of ammonium sulfate (solute) as shown below:

$n_{solute}=M*V_{solution}=1.25\frac{mol}{L}*325mL*\frac{1L}{1000mL} \\\\n_{solute}=0.406mol(NH_4)_2SO_4$

Best regards.

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Answer:

See explanation

Explanation:

Hello there!

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2 years ago

A patient needs to be given exactly 1000 ml of a 5.0% (w/v) intravenous glucose solution. the stock solution is 55% (w/v). how m

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