Question

How many moles are in 325mL of 1.25M (NH4)2SO4

Answer 1

Answer:

$n_{solute}=0.406mol(NH_4)_2SO_4$

Explanation:

Hello,

In this case, since the molarity is defined as the ratio of the moles of the solute to the volume of the solution in liters:

$M=\frac{n_{solute}}{V_{solution}}$

For the given volume and molarity, we solve for the moles of ammonium sulfate (solute) as shown below:

$n_{solute}=M*V_{solution}=1.25\frac{mol}{L}*325mL*\frac{1L}{1000mL} \\\\n_{solute}=0.406mol(NH_4)_2SO_4$

Best regards.