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Nataliya [291]
3 years ago
6

How many moles are in 325mL of 1.25M (NH4)2SO4

Chemistry
1 answer:
mote1985 [20]3 years ago
4 0

Answer:

n_{solute}=0.406mol(NH_4)_2SO_4

Explanation:

Hello,

In this case, since the molarity is defined as the ratio of the moles of the solute to the volume of the solution in liters:

M=\frac{n_{solute}}{V_{solution}}

For the given volume and molarity, we solve for the moles of ammonium sulfate (solute) as shown below:

n_{solute}=M*V_{solution}=1.25\frac{mol}{L}*325mL*\frac{1L}{1000mL}  \\\\n_{solute}=0.406mol(NH_4)_2SO_4

Best regards.

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It ends up like this:

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Source(s):
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<em>Good luck, hope this helps :)</em>

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