Answer:
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With determination and hard work, people can overcome difficult challenges. How do the people of Greensburg, Kansas, and Chicago, Illinois, illustrate this idea? Use details from both texts to support your response. i cant do it
Explanation:
Answer:
The displacement reactions are regarded as redox reactions because they involve the formal transfer of electrons from one chemical specie to the other
2) The series of reactivity of the metals in the order of increasing reactivity are;
↓
↓
Explanation:
1) Redox (oxidation-reduction) reaction is a chemical reaction involving the loss and gain of electrons from one chemical species to another, where the chemical species that undergoes oxidation, loses electrons and is termed the reducing agent, while the other chemical species that undergoes reduction, gains electrons, and is termed the oxidizing agent
2) The redox reaction can being based on the affinity for electrons depends on the positions of the reactants in the electrochemical series as well as the chemical reactivity of the metals with zinc being a stronger reducing agent and more chemically reactive than copper and magnesium being a stronger reducing agent and more chemically reactive than zinc
Least reactive (Cu) < (Zn) < Mg Most reactive
Copper < Zinc < Magnesium.
Increases to a small extent, because the buffer resists change in pH.
<h3>What do you mean by buffer?</h3>
A buffer is a substance that can withstand a pH change when acidic or basic substances are added. Small additions of acid or base can be neutralized by it, keeping the pH of the solution largely constant. For procedures and/or reactions that call for particular and stable pH ranges, this is significant. The pH range and capacity of buffer solutions determine how much acid or base can be neutralized while pH changes and how much pH will vary. A buffer must have a weak conjugate acid-base pair, which can be either an or b, in order to successfully maintain a pH range.
To learn more about buffers, refer to:
brainly.com/question/602584
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Density is sensitive to temperature for gases and liquids, although not much for liquids. We use the data in the picture. Using linear interpolation, we determine the densities at 11°C and 20°C.
@20°C: Density = 0.99823 g/cm³ or g/mL
@11°C:
(10 - 11)/(10 - 20) = (0.99973 - Density)/(0.99973 - 0.99823)
Solving for density:
Density = 0.99958 g/cm³ or g/mL
Mass @ 20°C = 100 mL * 0.99823 g/mL = 99.823 g
Mass @ 11°C = 100 mL * 0.99958 g/mL = 99.958 g
Difference of Masses = |99.823 g - 99.958 g| = 0.135 g