Question in picture #8 and 9 answer with explanation and you’ll get brainlist ZOOM IN

an engineer wishes to design a container that will hold 12.0 mol of ethane at a pressure no greater than 5.00x10*2 kPa and a tem

OleMash [197]

Answer:

The minimum volume of the container is 0.0649 cubic meters, which is the same as 64.9 liters.

Explanation:

Assume that ethane behaves as an ideal gas under these conditions.

By the ideal gas law,

$P\cdot V = n\cdot R\cdot T$ ,

$\displaystyle V = \frac{n\cdot R\cdot T}{P}$ .

where

$P$ is the pressure of the gas,
$V$ is the volume of the gas,
$n$ is the number of moles of particles in this gas,
$R$ is the ideal gas constant, and
$T$ is the absolute temperature of the gas (in degrees Kelvins.)

The numerical value of $R$ will be $8.314$ if $P$ , $V$ , and $T$ are in SI units. Convert these values to SI units:

$P =\rm 5.00\times 10^{2}\;kPa = 5.00\times 10^{2}\times 10^{3}\; Pa = 5.00\times 10^{5}\; Pa$ ;
$V$ shall be in cubic meters, $\rm m^{3}$ ;
$T = \rm 52.0 \textdegree C = (52.0 + 273.15)\; K = 325.15\; K$ .

Apply the ideal gas law:

$\displaystyle \begin{aligned}V &= \frac{n\cdot R\cdot T}{P}\\ &= \frac{12.0\times 8.314\times 325.15}{5.00\times 10^{5}}\\ &= \rm 0.0649\; m^{3} \\ &= \rm (0.0649\times 10^{3})\; L \\ &=\rm 64.9\; L\end{aligned}$ .

4 0

4 years ago

Positive Deviation from Raoult's Law occurs when the vapour pressure of component is greater than what is expected in Raoult's L

8090 [49]

Answer:

All of the above.

Explanation:

In positive deviation from Raoult's Law occur when the vapour pressure of components is greater than what is expected value in Raoult's law.

When a solution is non ideal then it shows positive or negative deviation.

Let two solutions A and B to form non- ideal solutions.let the vapour pressure of component A is $P_A$ and vapour pressure of component B is $P_B$ .

$P^0_A$ = Vapour pressure of component A in pure form

$P^0_B$ = Vapour pressure of component B in pure form

$x_A$ =Mole fraction of component A

$x_B=$ =Mole fraction of component B

The interaction between A- B is less than the interaction A- A and B-B interaction.Therefore, the escaping tendency of liquid molecules in mixture is greater than the escaping tendency in pure form.Hence, the vapour pressure of a mixture is greater than the initial value of vapour pressure.

$P_A >P^0_A\cdot x_A$ , $P_B>P^0_B\cdot x_B$

Therefore, $P_A+P_B >P^0_A\cdot x_A+P^0_B \cdot x_B$

Therefore, the enthalpy of mixing is greater than zero and change in volume is greater than zero.

Hence, option a,b,c and d are true.

6 0

4 years ago

What is the net ionic equation for the precipitation reaction between BaCl2 and Na2So4? I know the answer ( Ba2+(aq) + SO42-(aq)

elixir [45]

Answer:

Net ionic equation:

Ba²⁺(aq) + SO₄²⁻(aq) → BaSO₄(s)

Explanation:

Chemical equation:

BaCl₂ + Na₂SO₄ → BaSO₄ + NaCl

Balanced Chemical equation:

BaCl₂(aq) + Na₂SO₄(aq) → BaSO₄(s) + 2NaCl(aq)

Ionic equation:

Ba²⁺(aq) + 2Cl⁻(aq) + 2Na⁺(aq) + SO₄²⁻(aq) → BaSO₄(s)+ 2Na⁺(aq) + 2Cl⁻ (aq)

Net ionic equation:

Ba²⁺(aq) + SO₄²⁻(aq) → BaSO₄(s)

The Cl⁻(aq) and Na⁺ (aq) are spectator ions that's why these are not written in net ionic equation. The BaSO₄ can not be splitted into ions because it is present in solid form.

Spectator ions:

These ions are same in both side of chemical reaction. These ions are cancel out. Their presence can not effect the equilibrium of reaction that's why these ions are omitted in net ionic equation.

5 0

3 years ago

Which non-metal is a liquid at room temperature

bixtya [17]

The only nonmetal that is liquid at room temperature is the element Br or Bromine. When we say at room temperature, it means at zero degrees Celsius and at one atmospheric pressure. The metal that is liquid at room temperature is the element Hg or mercury.

4 0

3 years ago

Read 2 more answers

What is the empirical formula for a substance if a 201.6 g sample of it contains 54.0 grams of nitrogen, 15.0 grams of hydrogen,

jeyben [28]

The empirical formula of the substance would be $NH_4Cl$

<h3>Empirical formula calculation</h3>

The constituents of the compound are as follows:

N = 54/201.6 = 26.78% = 26.78/14 = 1.91 moles

H = 15/201.6 = 7.44% = 7.44/1 = 7.44 moles

Cl = 132.6/201.6 = 65.48% = 65.48/35.5 = 1.84 moles

Divide the number of moles by the smallest"

N = 1.91/1.84 = 1

H = 7.44/1.84 = 4

Cl = 1.84/1.84 = 1

Thus, the empirical formula is $NH_4Cl$

More on empirical formula can be found here: brainly.com/question/14044066

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6 0

2 years ago