The average rate of change of the function f( x ) = x² + 7x + 6 at the interval of −4 ≤ x ≤ −1 is 2
<h3>What is the average rate of change the function?</h3>
The average rate of change the function is simply the change in y-values of the two points divided by the change in x-values of the two points.
It is expressed as;
Given the data in the question;
- f( x ) = x² + 7x + 6
- Interval: −4 ≤ x ≤ −1 ⇒ [-4.-1]
Average rate of change = ( f(-1) - f(-4) ) / ( (-1) - (-4) )
Average rate of change = ( (-1)² + 7(-1) + 6 ) - ( (-4)² + 7(-4) + 6 ) ) / ( (-1) - (-4) )
Average rate of change = ( (1 + -7 + 6 ) - ( 16 - 28 + 6 ) ) / (-1 + 4 )
Average rate of change = ( ( 0 ) - ( -6 ) ) / (-1 + 4 )
Average rate of change = ( 0 + 6 ) / ( 3 )
Average rate of change = 6 / 3
Average rate of change = 2
Therefore, the average rate of change of the function is 2.
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Answer:
This is because √-1 is<em> i</em>, which is an extension of real numbers called complex numbers.
Step-by-step explanation:
A real number is one that can be expressed in decimal form.Real numbers are those that appear on the number line.In mathematics, √-1 is i which is an extension of real numbers to represent complex numbers.
Which one is it on that page
Answer:
x = 9
Step-by-step explanation:
7x + 3 = 10x -24
3 = 10x -7x - 24
24 + 3 = 10x - 7x
27 = 3x
27/3 = 3x/3
9= x
x = 9
Is this supposed to be simplified orrr?