Pls help me 10 points

nirvana33 [79]

Hi!

The answer is no, because the y values have no pattern, nor are they proportional with the x values.

Hope this helps! :)
-Peredhel

3 0

2 years ago

Read 2 more answers

In a shipment of 71 vials, only 13 do not have hairline cracks. If you randomly select 2 vials from the shipment, what is the pr

yanalaym [24]

Answer:

0.0313

Step-by-step explanation:

Given that in the shipment of 71 vials, only 13 do not have hairline cracks

Probability of not having a hairline cracks = $\frac{13}{71}$

If you randomly select 2 vials from the shipment

(Probability of not having a hairline cracks)' = $\frac{13-1}{71-1}$ = $\frac{12}{70}$

what is the probability that none of the 2 vials have hairline cracks.

i.e $(\frac{13}{71}) * (\frac{12}{70})$

= 0.183 × 0.171

= 0.0313

Hence, the probability that none of the 2 vials have hairline cracks = 0.0313

6 0

3 years ago

Linear Algebra: Permutation Matrices Let M be the matrix {{0,0,0,1,0}, {0,0,1,0,0}, {0,1,0,0,0}, {0,0,0,0,1}{1,0,0,0,0}}. What i

FromTheMoon [43]

Multiplying M by any matrix A would return new matrix, B, in which

• the 1st row of B is equal to the 4th row of A,

• the 2nd row of B is equal to the 3rd row of A,

• the 3rd row of B is equal to the 2nd row of A,

• the 4th row of B is equal to the 5th row of A, and

• the 5th row of B is equal to the 1st row of A.

The pattern here is

1 => 4 => 5 => 1

2 => 3 => 2

Let {4, 3, 2, 5, 1} denote the matrix M, where each number refers to the row of the identity matrix, I.

Using this notation, the pattern above gives

M² = {5, 2, 3, 1, 4}

M³ = {1, 3, 2, 4, 5}

M⁴ = {4, 2, 3, 5, 1}

M⁵ = {5, 3, 2, 1, 4}

M⁶ = {1, 2, 3, 4, 5}

so that <em>n</em> = 6.

(Notice that the first cycle has length 3 and the second one has length 2; the minimum <em>n</em> needed here is then LCM(2, 3) = 6.)

6 0

2 years ago

What is the relationship between ∠HIK and ∠JIK?

blagie [28]

Complementary angles --- they add up to 90 degrees

4 0

2 years ago

For each diagram, describe a translation, rotation, or reflection that takes line ℓ to line ℓ′. Then plot and label A′ and B′, t

inn [45]

Answer:

translate down 3
reflect across the horizontal line through A

Step-by-step explanation:

1. There are many transformations that will map a line to a parallel line. Translation either horizontally or vertically will do it. Reflection across a line halfway between them will do it, as will rotation 180° about any point on that midline.

In the first attachment, we have elected to translate the line down 3 units.

__

2. Again, there are many transformations that could be used. Easiest is one that has point A as an invariant point, such as rotation CW or CCW about A, or reflection horizontally or vertically across a line through A.

Any center of rotation on a horizontal or vertical line through A can also be used for a rotation that maps one line to the other.

In the second attachment, we have elected to reflect the line across a horizontal line through A.

6 0

2 years ago