Answer:
The child has 6 dimes and 5 quarters.
Step-by-step explanation:
Let q and d represent the number of quarters and of dimes respectively.
Then q + d = 11 (Equation A), and ($0.25/quarter)q + ($0.10/dime)d = $1.85 (Equation B).
Multiply the 2nd equation by 100 to remove the decimal fractions:
25q + 10d = 185 (Equation C)
Now multiply the 1st equation by -10 to obtain -10q - 10d = -110 (Equation D), and combine this result with Equation C:
-10q - 10d = -110
25q + 10d = 185
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15q = 75, and so q = 75/15 = 5.
According to Equation A, q + d = 11. Replacing q with 5, we get:
5 + d = 11, and so d = 6.
The child has 6 dimes and 5 quarters.
Answer:
I'm not so sure what you mean from your question but if we discussed the Average of 11 and 35( positive integers), we would say that it's 23<u>.</u>
Answer:
y = -4x +2
Step-by-step explanation:
As x-values increase by 1, y-values decrease by 4. The slope of the line is ...
... m = (change in y)/(change in x) = -4/1 = -4
We can use the first (x, y) pair as a point to use in the point-slope form of the equation of a line. That form can be written, for slope m and point (h, k) ...
... y = m(x -h) +k
using m = -4 and (h, k) = (1, -2), we can fill in the numbers to get ...
... y = -4(x -1) -2
... y = -4x +4 -2 . . . . eliminate parentheses
... y = -4x +2 . . . . . . slope-intercept form
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<em>Alternate approach</em>
After you recognize that a change in x of 1 gives a change in y of -4, you can work backward one step to find the table value for y corresponding to x=0. That will be -2+4 = +2. Now, you know both the slope (-4) and the y-intercept (+2), so you can write the equation directly from this knowledge:
... y = -4x +2
Answer:
The dependent variable is the final grade in the course and is the vriable of interest on this case.
H0: 
H1: 
And if we reject the null hypothesis we can conclude that we have a significant relationship between the two variables analyzed.
Step-by-step explanation:
On this case w ehave the following linear model:
Where Y represent the final grade in the course and X the student's homework average. For this linear model the slope is given by 
and the intercept is 
Which is the dependent variable, and why?
The dependent variable is the final grade in the course and is the vriable of interest on this case.
Based on the material taught in this course, which of the following is the most appropriate alternative hypothesis to use for resolving this question?
Since we conduct a regression the hypothesis of interest are:
H0:
H1:
And if we reject the null hypothesis we can conclude that we have a significant relationship between the two variables analyzed.
Answer:
C. 5
Step-by-step explanation:
Use the Distance Formula.
Substitute the values of x1 , y1 , x2 , and y2 .
|AB|² =|(1--2)²+(10-6)²|
|AB|² = |9+16|
|AB| = √ 25
|AB| =5
