Yes.<span>a multiple of 3=add the numbers so 8 plus 1 is 9 and divide that by 3 it works 2.no.</span>fthe number formed by its last two digits is divisible by 4, the original number is as well. 3.no.take the last digit, double it, and subtract it from the rest of the number. 4.yes.<span>Add the digits. If that sum is divisible by nine, then the original number is as well.</span> <span>5.no . has to work with both </span><span>Multiple of 2 --> is even (ends with 0, 2, 4, 6 or 8) </span> <span>Multiple of 3 --> digits add up to a multiple of 3. </span>
I broke it all the way day half of 51 is 25 in a half and half of 25 is 12 in half so if Jimmy lifted twice as much he may have lifted 25 in a half and bob left 12