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Wewaii [24]
2 years ago
9

1.) Is 81 a multiple of 3? Explain how you know

Mathematics
1 answer:
jek_recluse [69]2 years ago
7 0
Yes.<span>a multiple of 3=add the numbers so 8 plus 1 is 9 and divide that by 3 it works
2.no.</span>fthe number formed by its last two digits is divisible by 4, the original number is as well. 
3.no.take the last digit, double it, and subtract it from the rest of the number. 
4.yes.<span>Add the digits. If that sum is divisible by nine, then the original number is as well.</span>
<span>5.no . has to work with both
</span><span>Multiple of 2 --> is even (ends with 0, 2, 4, 6 or 8) </span>
<span>Multiple of 3 --> digits add up to a multiple of 3. </span>
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Suppose "35" cars start at a car race. In how many ways can the top 3 cars finish the​ race?
Thepotemich [5.8K]

Answer:

The  value  is   \left 35  } \atop }} \right. P_3  =  39270

Step-by-step explanation:

From the question we are told that

    The  total number of cars is  n  =  35

     The  number cars considered is  r = 3

Generally the number of different top three finishes possible for this race of 35 cars  is mathematically represented as

       \left n } \atop }} \right. P_r  =   \frac{n!}{(n - r) !}

       \left 35  } \atop }} \right. P_3  =   \frac{35! }{(35 - 3) !}

       \left 35  } \atop }} \right. P_3  =   \frac{35 *  34 *  33 *  32! }{32 !}

       \left 35  } \atop }} \right. P_3  =  39270

7 0
2 years ago
What is (-0.8)(-0.8)(-0.8)
puteri [66]
The answer would be -0.512
You would get this answer because -0.8 times -0.8 equals 0.64. Positive 0.64 times negative 0.8 would result In -0.512
8 0
2 years ago
Read 2 more answers
Bir sınıftaki erkekletin sayısının kızların sayısına oranı 3 bölü 4 tür . sınıftaki kız öğrencilerin sayısı 12 ise erkek oğrenci
VikaD [51]

Answer:

Ha?what do you mean ba? Jjsjsjsjjsjs

5 0
2 years ago
Read 2 more answers
A) 0,2 x 5/7 + 11/14 = ?
NemiM [27]
I hope this helps you

6 0
3 years ago
Read 2 more answers
Please help! Thanks in advance.
alukav5142 [94]
In this problem, we need to plug in the given x values for f(x)=0 and find a and b.

When we plug in 1, we get: 2 \times {1}^{4} - 5 \times {1}^{3} - 14 \times {1}^{2} + a \times 1 + b = 0

Simplify:
2 - 5 - 14 + a + b = 0
- 17 + a + b = 0
a + b = 17

We got our first statement about the values of the variables. If we find one more we can find those 2 variables.

We have another given root: 4.

Plug it in:
2 \times {4}^{4} - 5 \times {4}^{3} - 14 \times {4}^{2} + a \times 4 + b = 0
512 - 320 - 224 + 4a + b = 0
- 32 + 4a + b = 0
4a + b = 32

Now we have our second one. We can combine them:
a + b = 17 \\ 4a + b = 32

I use elimination method which is easier here.

Multiply the top equation by -1: - a - b = - 17 \\ 4a + b = 32

Add them up:
3a = 15

Simplify:
a = 5

Now we have a, we can plug in one of those equations to find b:
5 + b = 17
b = 17 - 5
b = 12

So, the answers are a=5 and b=12 .
6 0
3 years ago
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