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MariettaO [177]
3 years ago
10

What are the zeros of this function? Circle them on the graph.

Mathematics
1 answer:
Rashid [163]3 years ago
8 0

Given:

The graph of a function.

To find:

The zeros of this function on the graph.

Solution:

We know that, zeros are the values at which the values of the function is 0. It means, the points where the graph of function intersect the x-axis are know as zeros of the function.

From the given graph it is clear that, the graph intersect the x-axis at two points.

Therefore, the marked points on the below graph are the zeros of the function.

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PLEASE HELP ME SOLVE THIS ​
klio [65]

Answer:

y = 90°

Step-by-step explanation:

The left side base angle of the triangle and the angle of 110° form a straight angle and are supplementary, thus

base angle = 180° - 110° = 70°

The right base angle is also 70° , thus the triangle is isosceles

The line segment from the vertex is a perpendicular bisector, hence

y = 90°

4 0
3 years ago
Exercise 30 please , show work
ArbitrLikvidat [17]
-8(2a-3b)-5(6b-4a)=\\=-8 \times 2a -8 \times (-3b)-5 \times 6b-5 \times (-4a)= \\
=-16a+24b-30b+20a= \\
=20a-16a+24b-30b= \\
=(20-16)a+(24-30)b= \\
=4a-6b
3 0
3 years ago
Read 2 more answers
To make chocolate ice cream,you need about 3/8 pound of chocolate.How many pounds of chocolate will you need to make 4 batches o
Gre4nikov [31]
1 batch ice cream = 3/8 lb chocolate

4 batches ice cream=
=4(3/8)
=(4*3)/8
=12/8
=1 1/2 pounds of chocolate needed to make 4 batches of ice cream

Hope this helps! :)
8 0
3 years ago
¿cuanto pesa cada uno de nuestros 3 personajes?
sergij07 [2.7K]

Resolviendo el sistema de ecuaciones veremos que:

  • niña = 23kg
  • niño = 28kg
  • perro = 18kg.

<h3>¿Como resolver el sistema de ecuaciones?</h3>

Aqui tenemos el sistema de ecuaciones:

Niña + niño = 51kg

Niño + perro = 46 kg

Niña + perro = 41kg

Para resolver esto, lo primero que debemos hacer es aislar una variable en una de las ecuaciones, por ejemplo, podriamos aislar "perro" en la tercera:

perro = 41kg - niña

Ahora reemplazamos eso en la segunda para obtener:

niño + (41kg - niña) = 46kg

niño - niña = 46kg - 41kg = 5kg

niño = niña + 5kg

Ahora logramos obtener la variable "niño" en terminos de la variable "niña". Podemos reemplazar esto en la primera ecuacion del sistema.

niña + niño = 51kg

niña + (niña + 5kg) = 51kg

2*niña = 51kg - 5kg = 46kg

niña = 46kg/2 = 23kg.

Ahora que sabemos esto, usamos las otras ecuaciones para encontrar el peso del niño y el perro:

niño = niña + 5kg = 23kg + 5kg = 28kg

perro = 41kg - niña = 41kg - 23kg = 18kg.

Sí quieres aprender más sobre sistemas de ecuaciones, puedes leer:

brainly.com/question/17174746

6 0
2 years ago
Two different suppliers, A and B, provide a manufacturer with the same part. All supplies of this part are kept in a large bin.
koban [17]

Answer:

The probability of selecting a non-defective part provided by supplier A is 0.807.

Step-by-step explanation:

Let <em>A</em> = a part is supplied by supplier A, <em>B</em> = a part is supplied by supplier B and <em>D</em> = a part is defective.

<u>Given</u>:

P (D|A) = 0.05, P(D|B) = 0.09

A supplies four times as many parts as B, i.e. n (A) = 4 and n (B) = 1.

Then the probability of event <em>A</em> and <em>B</em> is:

P(A)=\frac{n(A)}{n(A)+N(B)}= \frac{4}{4+1}=0.80\\P(B)\frac{n(B)}{n(A)+N(B)}= \frac{1}{4+1}=0.20

Compute the probability of selecting a defective product:

P(D)=P(D|A)P(A)+P(D|B)P(B)\\=(0.05\times0.80)+(0.09\times0.20)\\=0.058

The probability of selecting a non-defective part provided by supplier A is:

P(A|D')=\frac{P(D'|A)P(A)}{P(D')} = \frac{(1-P(D|A))P(A)}{1-P(D)}\\=\frac{(1-0.05)\times0.80}{(1-0.058)}\\ =0.80679\\\approx0.807

Thus, the probability of selecting a non-defective part provided by supplier A is 0.807.

5 0
3 years ago
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