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MariettaO [177]
3 years ago
10

What are the zeros of this function? Circle them on the graph.

Mathematics
1 answer:
Rashid [163]3 years ago
8 0

Given:

The graph of a function.

To find:

The zeros of this function on the graph.

Solution:

We know that, zeros are the values at which the values of the function is 0. It means, the points where the graph of function intersect the x-axis are know as zeros of the function.

From the given graph it is clear that, the graph intersect the x-axis at two points.

Therefore, the marked points on the below graph are the zeros of the function.

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6
Anton [14]

Answer:

(-3, 3)

Step-by-step explanation:

y = x + 6

y = -2x - 3

x+6= -2x-3

3x = -9

x = -3

put x = -3  : y = -3+6 =3

7 0
2 years ago
Suppose you round 43,257,529 to 43,300,000. To what place value did you round the number?
yanalaym [24]
To the one hundred thousands

4 0
3 years ago
Read 2 more answers
Help needed! - Geometry - 15 points - One question -
il63 [147K]

Answer: m<VUT= 70 degrees

Step-by-step explanation:

120= 50+ ?

?=70

6 0
3 years ago
Ignore the blue and 13. But I don’t understand dividing the polynomials. It says to complete the problem.
Virty [35]
OK the next step is to multiply 3r -1 by -7r
this gives us -21r^2 + 7r  and we write it below -21r^2 + 25r
and subtract 
This gives us  18r and we bring down the -6   to give
18r - 6

Finally we divide  18r by  -3r   to give  -6 then  add - 6 to the r^2 - 7r on the top 
then multiply -3r - 1 by -6 to give 18r - 6
subtraction then leaves nothing.

so the answer is r^2 - 7r - 6

4 0
3 years ago
Find the center and radius of this
ipn [44]

\text{Hello there! :)}

Answer:

\boxed{\text{Center at } (7, -4), \text{ Radius of } 7.}

\text{Formula for a circle: }  (x - h)^{2} + (y - k)^{2}  = r^{2}  \text{ Where:}

h = \text{ x-coordinate of center}\\\\k = \text{ y-coordinate of center}\\\\r = \text{ radius}\\\\\text{Therefore:}

\text{In the equation } (x - 7)^{2}  + (y + 4)^{2}  = 49:

h = 7\\\\k = -4\\\\r = \sqrt[]{49} = 7 \\\\\text{So:}

\text{Center at } (7, -4), \text{ Radius of } 7.

3 0
3 years ago
Read 2 more answers
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