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3 years ago

5

Find the value of kk for which the constant function x(t)=kx(t)=k is a solution of the differential equation 3t3dxdt+5x−3=03t3dx

dt+5x−3=0.

1 answer:

Dafna11 [192]3 years ago

7 0

If $x(t)=k$ is constant, then $\dfrac{\mathrm dx}{\mathrm dt}=0$ , so you have

$5k-3=0\implies k=\dfrac35$

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