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dimulka [17.4K]
3 years ago
9

On your first attempt you leave the surface of the earth at v = 5534 m/s. how far from the center of the earth will you get?

Physics
1 answer:
Tamiku [17]3 years ago
8 0
<span>It's another energy balance equation, though: energy to start with is the same as energy that you end with. Suppose that we start a distance r0 from the Earth and end a distance r1 from the Moon, then the energy balance gives: 1 v02 - G M / r0 - G m / (D - r0) = 1 v12 - G M / (D - r1) - G m / r1 ...where m is the moon's mass. One simple limit takes D ? ? and 1 v02 ? G M / r0 (the escape velocity equation), to yield: 1 v12 ? G M / r1 v1 ? ?( 2 G M / r1 ) = 2377 m/s.</span>
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When 15 newtons of force is applied to the 0.5 kg book, the friction keeps the book from sliding down the wall. What is the mini
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Answer:

15 N and 3.061

Explanation:

From the question,

The minimum force of friction to keep the book from sliding = 15 N.

using

F = mgμ................. Equation 1

Where F = Frictional Force, m = mass of the book, g = acceleration due to gravity, μ = coefficient of friction.

make μ the subject of the equation

μ = F/mg............... Equation 2

Given: F = 15 N, m = 0.5 kg, g = 9.8 m/s²

Substitute into equation 2

μ = 15(0.5×9.8)

μ = 15/4.9

μ = 3.061

Hence the coefficient of friction to keep the book from sliding = 3.061

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