Answer:
ΔT = 13.65° C
ΔQ = 13.7 J
Explanation:
First we will find the final temperature of air by using equation of state:
P₁V₁/T₁ = P₂V₂/T₂
For Isochoric Process, V₁ = V₂
Therefore,
P₁/T₁ = P₂/T₂
T₂ = P₂T₁/P₁
where,
T₂ = Final Temperature = ?
P₂ = Final Pressure = 1050 mb
P₁ = Initial Temperature = 1000 mb
T₁ = Initial Temperature = 0°C = 273 k
Therefore,
T₂ = (1050 mb)(273 K)/(1000 mb)
T₂ = 286.65 K
Change in Temperature = ΔT = T₂ - T₁
ΔT = 286.65 K - 273 K
<u>ΔT = 13.65° C</u>
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The first law of thermodynamics can be written as:
ΔQ = ΔU + W
where,
ΔQ = heat absorbed
ΔU = change in internal energy = mCΔT
W = Work Done = 0 (in case of isochoric process)
Therefore.
ΔQ = mCΔT
where,
m = mass of air = 1 g = 1 x 10⁻³ kg
C = specific heat of dry air = 1003.5 J/kg.°C
Therefore,
ΔQ = (1 x 10⁻³ kg)(1003.5 J/kg.°C)(13.65°C)
<u>ΔQ = 13.7 J</u>
Answer:.
Coriolis effect and Temperature differences between the equator and the polar areas.
Explanation:
Global winds are created by both the spin of the Earth (Coriolis effect) and the differences in temperature between the equator and the polar areas. These winds are often grouped together as trade winds, easterlies, and westerlies.
Between B and C, the object was going at a constant velocity; it is going 60 m/min consistently for that time frame.
(This is from experience so sorry if it's wrong but) When wind instruments are played, sometimes the notes go flat or sharp depending on the speed the player blows air into the instrument as well as the warmth of the air. When playing a string instrument, the pitch can be changed in many ways. For example, when the player places their fingers on the string depending on which part of the tip of the finger you use, the tone of the sound and sometimes the pitch, changes. Looking at the question in a different way, you can change the pitch and the range of notes you can reach on the instrument (both wind and string) by changing the note you tune your instrument to. Hope this helps!!
