applied forces would be push for example.
normal forces would seem to be a force such as gravity.
friction for example when you try to slide on carpet but the fabric or whatever its made of stops you.
Answer:
a)![v=13.2171\,m.s^{-1}](https://tex.z-dn.net/?f=v%3D13.2171%5C%2Cm.s%5E%7B-1%7D)
b)![H=8.9605\,m](https://tex.z-dn.net/?f=H%3D8.9605%5C%2Cm)
Explanation:
Given:
mass of bullet, ![m=4.97\times 10^{-3}\,kg](https://tex.z-dn.net/?f=m%3D4.97%5Ctimes%2010%5E%7B-3%7D%5C%2Ckg)
compression of the spring, ![\Delta x=0.0476\,m](https://tex.z-dn.net/?f=%5CDelta%20x%3D0.0476%5C%2Cm)
force required for the given compression, ![F=9.12 \,N](https://tex.z-dn.net/?f=F%3D9.12%20%5C%2CN)
(a)
We know
![F=m.a](https://tex.z-dn.net/?f=F%3Dm.a)
where:
a= acceleration
![9.12=4.97\times 10^{-3}\times a](https://tex.z-dn.net/?f=9.12%3D4.97%5Ctimes%2010%5E%7B-3%7D%5Ctimes%20a)
![a\approx 1835\,m.s^{-2}\\](https://tex.z-dn.net/?f=a%5Capprox%201835%5C%2Cm.s%5E%7B-2%7D%5C%5C)
we have:
initial velocity,![u=0\,m.s^{-1}](https://tex.z-dn.net/?f=u%3D0%5C%2Cm.s%5E%7B-1%7D)
Using the eq. of motion:
![v^2=u^2+2a.\Delta x](https://tex.z-dn.net/?f=v%5E2%3Du%5E2%2B2a.%5CDelta%20x)
where:
v= final velocity after the separation of spring with the bullet.
![v^2= 0^2+2\times 1835\times 0.0476](https://tex.z-dn.net/?f=v%5E2%3D%200%5E2%2B2%5Ctimes%201835%5Ctimes%200.0476)
![v=13.2171\,m.s^{-1}](https://tex.z-dn.net/?f=v%3D13.2171%5C%2Cm.s%5E%7B-1%7D)
(b)
Now, in vertical direction we take the above velocity as the initial velocity "u"
so,
![u=13.2171\,m.s^{-1}](https://tex.z-dn.net/?f=u%3D13.2171%5C%2Cm.s%5E%7B-1%7D)
∵At maximum height the final velocity will be zero
![v=0\,m.s^{-1}](https://tex.z-dn.net/?f=v%3D0%5C%2Cm.s%5E%7B-1%7D)
Using the equation of motion:
![v^2=u^2-2g.h](https://tex.z-dn.net/?f=v%5E2%3Du%5E2-2g.h)
where:
h= height
g= acceleration due to gravity
![0^2=13.2171^2-2\times 9.8\times h](https://tex.z-dn.net/?f=0%5E2%3D13.2171%5E2-2%5Ctimes%209.8%5Ctimes%20h)
![h=8.9129\,m](https://tex.z-dn.net/?f=h%3D8.9129%5C%2Cm)
is the height from the release position of the spring.
So, the height from the latched position be:
![H=h+\Delta x](https://tex.z-dn.net/?f=H%3Dh%2B%5CDelta%20x)
![H=8.9129+0.0476](https://tex.z-dn.net/?f=H%3D8.9129%2B0.0476)
![H=8.9605\,m](https://tex.z-dn.net/?f=H%3D8.9605%5C%2Cm)
Answer:
From Wikipedia:
"A synovial joint, also known as diarthrosis, joins bones or cartilage with a fibrous joint capsule that is continuous with the periosteum of the joined bones, constitutes the outer boundary of a synovial cavity, and surrounds the bones' articulating surfaces. The synovial cavity/joint is filled with synovial fluid."
Answer:
it's C
Explanation:
have a nice day............
Well sorry but this is the wrong language.