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kirza4 [7]
3 years ago
11

These has two questions, any help would be much appreciated. Ignore the current answers.

Physics
1 answer:
Sati [7]3 years ago
4 0
Bro sorry I don’t know these answer but keeep trying
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Where would you find the sun on this HR diagram?
VLD [36.1K]

Answer:

C

Explanation:

That is where the most heat and light is showing on this diagram.

6 0
3 years ago
Help me please<br><img src="https://tex.z-dn.net/?f=%20%5C%5C%20" id="TexFormula1" title=" \\ " alt=" \\ " align="absmiddle" cla
poizon [28]

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2

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7 0
2 years ago
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Car A hits car B (initially at rest and of equal mass) from behind while going 15 m/s Immediately after the collision, car B mov
Mamont248 [21]

Given :

Initial speed of car A is 15 m/s and initial speed of car B is zero.

Final speed of car A is zero and final speed of car B is 10 m/s.

To Find :

What fraction of the initial kinetic energy is lost in the collision.

Solution :

Initial kinetic energy is :

K.E_i = \dfrac{15^2m}{2} + 0\\\\K.E_i = \dfrac{225 m}{2}

Final kinetic energy is :

K.E_f = \dfrac{10^2m}{2} + 0\\\\K.E_f = \dfrac{100m}{2}

Now, fraction of initial kinetic energy loss is :

Loss = \dfrac{\dfrac{225m}{2}-\dfrac{100m}{2}}{\dfrac{100m}{2}}\\\\Loss = \dfrac{125}{100}\\\\Loss = 1.25

Therefore, fraction of initial kinetic energy loss in the collision is 1.25 .

6 0
2 years ago
In what state of matter does oxygen exist at room temperature
denis-greek [22]
Oxygen is a gas a room temperature.


4 0
3 years ago
Read 2 more answers
The distance between two planets is 1600 km. How much time would the light
Snowcat [4.5K]

Answer:

5.33*10^-3 seconds

Explanation:

c = d/t

c = speed of light constant (3.0*10^5 km/s)

d = distance (1600 km)

t = ?

3.0*10^5 = 1600/t

t = 1600/3.0*10^5

t = 5.33*10^-3 seconds

I hope this helped! :)

6 0
3 years ago
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