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kifflom [539]
3 years ago
9

-------;wasthe head ofcholas, Chereas andpandyas​

Physics
1 answer:
IrinaVladis [17]3 years ago
5 0

Explanation:

the son of Vijayalaya, Aditya chola was the head of chola,cheras and pandyas..

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Light enter the container of the liquid at the angle 37° to the normal refraction beam makes an angle of 27° with the normal. Ca
Sliva [168]

Answer: 1.33

Explanation:

We would apply Snell's law which is expressed as

niSinθi = nrSinθr

where

θi = angle of incidence

θr = angle of refraction

ni = index of refraction of the incident medium(air)

nr = index of refraction of the refractive medium(liquid in this case)

From the information given,

ni = 1(index for air)

θi = 37

θr = 27

By substituting these values into the formula, we have

1 * sin37 = nr * sin27

nr = sin37/sin27

nr = 1.33

The index of the liquid is 1.33

6 0
1 year ago
Which of the following is an example of potential energy?
Papessa [141]

Answer:

A

Explanation:

potential energy is stored energy so the ball has potential energy to bounce or roll which would then have been converted to kinetic but the rest are in motion meaning energy is no longer stored but used in motion and therefore cannot be potential energy

4 0
3 years ago
A 3.1 kg ball is thrown straight upward with a speed of 18.2 m/s. Use conservation of energy to calculate the maximum height the
spayn [35]

Answer:

h = 16.9 m

Explanation:

When a ball is thrown upward, its velocity gradually decreases, until it stops for a moment, when it reaches the maximum height, while its height increases. Thus, the law conservation of energy states in this case, that:

Kinetic Energy Lost by Ball = Potential Energy Gained by Ball

(0.5)m(Vf² - Vi²) = mgh

h = (0.5)(Vf² - Vi²)/g

where,

Vf = Final Speed of Ball = 0 m/s (Since, ball stops for a moment at highest point)

Vi = Initial Speed of Ball = 18.2 m/s

g = acceleration due to gravity = - 9.8 m/s² ( negative for upward motion)

h = maximum height the ball can reach = ?

Therefore, using values in the equation, we get:

h = (0.5)[(0 m/s)² - (18.2 m/s)²]/(-9.8 m/s²)

<u>h = 16.9 m</u>

4 0
3 years ago
9. A car driver brakes gently. Her car slows down front --
sleet_krkn [62]

Answer:

9) This is a case of deceleration

10)-0.8 ms-2

b) acceleration is the change in velocity with time

11)

a) 100 ms-1

b) 100 seconds

12) 10ms-1

13) more information is needed to answer the question

14) - 0.4 ms^-2

15) 0.8 ms^-2

Explanation:

The deceleration is;

v-u/t

v= final velocity

u= initial velocity

t= time taken

20-60/50 =- 40/50= -0.8 ms-2

11)

Since it starts from rest, u=0 hence

v= u + at

v= 10 ×10

v= 100 ms-1

b)

v= u + at but u=0

1000 = 10 t

t= 1000/10

t= 100 seconds

12) since the sprinter must have started from rest, u= 0

v= u + at

v= 5 × 2

v= 10ms-1

14)

v- u/t

10 - 20/ 25

10/25

=- 0.4 ms^-2

15)

a=v-u/t

From rest, u=0

8 - 0/10

a= 8/10

a= 0.8 ms^-2

7 0
4 years ago
A pure musical torte causes a thin wooden
victus00 [196]
Hello! Your answer would be D. Interference

This is because interference causes vibration!!!
4 0
3 years ago
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