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Lorico [155]
3 years ago
12

HHEEELLP PLEASE I GIVE MARK BRAINLIEST!!!!!! HELP PLEASE!!!!!

Chemistry
1 answer:
Naily [24]3 years ago
7 0
1. <span>low melting point
2. </span>positive <span>ion
3. </span><span>There are 2 bromine atoms for every magnesium atom.
4. </span><span>The name of the positive ion.
5. </span>Sodium sulfide<span>
6. </span><span>A covalent bond with 2 pairs of shared electrons.
7. </span>valence electrons<span />
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The reactive properties or chemical behavior of an atom mostly depend on the number of
Kryger [21]
The reactive properties or chemical behavior of an atom is mostly dependant on the number of electrons in the outer shell
7 0
3 years ago
How many moles in .5g of sodium bromide?
Genrish500 [490]
I'm not sure how many sign fig's you are required to have.
However I think the final answer would be 0.05 Moles, because of the .5g, that is considered 1 sign fig.

6 0
3 years ago
6. How many moles of water would require 92.048 kJ of heat to raise its temperature from 34.0 °C to 100.0 °C? (3 marks)​
scoray [572]

Taking into account the definition of calorimetry, 0.0185 moles of water are required.

<h3>Calorimetry</h3>

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

Sensible heat is defined as the amount of heat that a body absorbs or releases without any changes in its physical state (phase change).

So, the equation that allows to calculate heat exchanges is:

Q = c× m× ΔT

where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.

<h3>Mass of water required</h3>

In this case, you know:

  • Heat= 92.048 kJ
  • Mass of water = ?
  • Initial temperature of water= 34 ºC
  • Final temperature of water= 100 ºC
  • Specific heat of water = 4.186 \frac{J}{gC}

Replacing in the expression to calculate heat exchanges:

92.048 kJ = 4.186 \frac{J}{gC}× m× (100 °C -34 °C)

92.048 kJ = 4.186 \frac{J}{gC}× m× 66 °C

m= 92.048 kJ ÷ (4.186 \frac{J}{gC}× 66 °C)

<u><em>m= 0.333 grams</em></u>

<h3>Moles of water required</h3>

Being the molar mass of water 18 \frac{g}{mole}, that is, the amount of mass that a substance contains in one mole, the moles of water required can be calculated as:

amount of moles=0.333 gramsx\frac{1 mole}{18 grams}

<u><em>amount of moles= 0.0185 moles</em></u>

Finally, 0.0185 moles of water are required.

Learn more about calorimetry:

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8 0
3 years ago
What is the density of nitrogen gas if 0.186 g occupies a volume of 110 mL?
Anvisha [2.4K]

Answer:

d=1.69\times 10^{-3}\ g/mL

Explanation:

Given that,

Mass, m = 0.186 g

Volume occupies, V = 110 mL

We need to find the density of Nitrogen gas. The mass per unit volume is called density of an object. It is given by the formula as follows :

d=\dfrac{m}{V}\\\\d=\dfrac{0.186\ g}{110\ mL}\\\\=1.69\times 10^{-3}\ g/mL

So, the required density is 1.69\times 10^{-3}\ g/mL.

4 0
3 years ago
1. What is oxidation? * O a. it is loss of electrons O b. it is gain of electrons O c. it is loss of protons O d. none of the ab
Lemur [1.5K]

Answer:

yes

Explanation:

who wants free points

7 0
3 years ago
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