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IRINA_888 [86]
3 years ago
13

What is the density of nitrogen gas if 0.186 g occupies a volume of 110 mL?

Chemistry
1 answer:
Anvisha [2.4K]3 years ago
4 0

Answer:

d=1.69\times 10^{-3}\ g/mL

Explanation:

Given that,

Mass, m = 0.186 g

Volume occupies, V = 110 mL

We need to find the density of Nitrogen gas. The mass per unit volume is called density of an object. It is given by the formula as follows :

d=\dfrac{m}{V}\\\\d=\dfrac{0.186\ g}{110\ mL}\\\\=1.69\times 10^{-3}\ g/mL

So, the required density is 1.69\times 10^{-3}\ g/mL.

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What is the name of the particle made up of 2 protons and 2 neutrons?
barxatty [35]

Answer: It’s called a alpha particle

Explanation:

8 0
3 years ago
Describes the difference between the formulas for nitrogen monoxide and nitrogen dioxide?
qwelly [4]

Answer:

nitrogen monoxide: NO

nitrogen dioxide: NO₂

Explanation:

Nitrogen monoxide is composed by 1 atom of O (prefix "mono-") and 1 atom of N. Nitrogen dioxide is composed by 2 atoms of O (prefix "di-") and 1 atom of N. As the oxigen atom in oxides has the valency -2 (it shares 2 electrons), the nitrogen has valency +2 in NO and +4 in NO₂.

6 0
3 years ago
How many grams of KCl are present in 55.0 mL of 2.10 M KCl?
sergiy2304 [10]

Answer:

none of the above is the answer

4 0
4 years ago
Read 2 more answers
When a liquid is cooled, the kinetic energy if the particles A. Decrease B. Increases C. Remains the same. The force of attracti
scoray [572]

Answer:

  • (A.) Kinetic energy decreases
  • (B.) Force of attraction increases
  • (C.) Space between particles remains the same

Explanation:

Kinetic energy is the energy in motion. Cooling if liquid would cause decreased temperature and hence slow down the oscillation of the particles.

Likewise, increased heat reduces the force of attraction between said particles, which allowed for their free movement. So the cooling would have opposite effect.

Finally, the space between the particles would remain the same as it was originally, as their force of attraction is increased in the cooling process, they would take the form they are held in.

I hope this was helpful and concise?

3 0
3 years ago
What is the reaction for CL^2 + 2 KBr —> 2 KCL+Br^2 of 11 grams of potassium bromide?
mylen [45]

Answer:

All the amounts of reactants and products are:

KBr

          11.0g (given)

          0.0924 mol

Cl₂

           0.0462 mol

           3.28g

KCl

           0.0924 mol

           6.89 g

Br₂

         0.0462 mol

         7.39 g

         

Explanation:

<u>1. Balanced chemical equation (given)</u>

   Cl_2+2KBr\rightarrow 2KCl+Br_2

<u>2. Mole ratios</u>

     \dfrac{1molCl_2}{2molKBr}

      \dfrac{2molKCl}{2molKBr}

     \dfrac{1molBr_2}{2molKBr}

<u />

<u>3. Molar masses</u>

  • Molar mass Cl₂: 70.906g/mol
  • Molar mass KBr: 119.002 g/mol
  • Molar mass KCl: 74.5513 g/mol
  • Molar mass KBr: 159.808 g/mol

<u>4. Convert 11 grams of potassium bromide to moles:</u>

  • #moles = mass in grams / molar mass
  • #mol KBr = 11g / 119.002g/mol = 0.092435mol KBr

<u>5. Use the mole ratios to find the amounts of Cl₂, KCl, and Br₂</u>

a) Cl₂

       \dfrac{1molCl_2}{2molKBr}\times 0.092435molKBr=0.0462molCl_2

        0.0462175molCl_2\times 70.906g/molCl_2=3.28gCl_2

b) KCl

       \dfrac{2molKCl}{2molKBr}\times0.092435molKBr=0.0924molKCl

      0.092435molKCl\times 74.5513g/molKCl=6.89gKCl

c) Br₂

       

         \dfrac{1molBr_2}{2molKBr}\times 0.092435molKBr=0.0462molBr_2

         0.0462175molBr_2\times 159.808g/molBr_2=7.39gBr2

The final calculations are rounded to 3 sginificant figures.

3 0
4 years ago
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