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3 years ago

The mean of 5 numbers is 30. The median is 33. What might the numbers be?

Mathematics

1 answer:

tatiyna3 years ago

4 0

Let a,b,c,d and e are five numbers

mean = (a +b+ c+ d+e)/5 = 30

⇒ (a +b+ c+ d+e) = 150_______(1)

now, Let the number excluded be a

then, new mean = (b+ c+ d+e)/4 = 28

⇒ (b+ c+ d+e)= 112

putting this value in (1),

⇒a + 112 = 150

⇒a = 150 -112 = 38

excluded number = 38

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Problem 4:

The line of regression is $\hat y = a+bx$ where:

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Problem 5:

The slope, $b=0.16$ , means that for every 1 point earned for a student's pre-exam total, their final exam score will increase by 0.16 points for each point they earned on the pre-exam.

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The y-intercept (or constant), $a=30.2$ , means that if a student's pre-exam total were 0, then they would expect to get a 30.2 on the final exam.

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Problem 8:

The fraction of variability (aka. coefficient of determination), $R^2$ , means that a certain proportion (or percentage) of the variance in the response variable can be explained by the explanatory variable. In context, this means that 36% of the variance in final exam scores can be explained by the pre-exam scores.