You know from the y-intercept that the equation will have a +y^2/12 term in it. Then for y=6, you have
.. 6^2/12 -x^2/b = 1
.. 2 = x^2/b
.. b = x^2/2
If your point is (2√3, 6), then this is
.. b = (2√3)^2/2 = 12/2 = 6
Then the hyperbola's equation is
.. y^2/12 -x^2/6 = 1 . . . . . . . . selection D
Answer:
8
Step-by-step explanation:
I don't know how to explain
9514 1404 393
Answer:
25 +0i
Step-by-step explanation:
The conjugate of a complex number is that number with the sign of the imaginary part reversed.
For z = -3+4i, its conjugate z* is -3-4i. The product of z and z* is ...
(-3 +4i)(-3 -4i) = -3(-3 -4i) +4i(-3 -4i)
= 9 +12i -12i -16i² = 9 +16 = 25
The real part of the product is 25; the imaginary part is 0.
(-3 +4i)(-3 -4i) = 25 +0i
_____
You may have noticed that (z)(z*) = |z|², the sum of the squares of the real and imaginary parts. It is always a non-negative real number.
To find out if the triangle is a right triangle, we must check if the following equation is true:
on the left side, we have:
and on the right side, we have:
since on both sides we get 625, we have that the brace forms a right triangle.
