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PolarNik [594]
3 years ago
14

PLEASE HELP!!Find the missing side length in the triangle below??

Mathematics
1 answer:
prisoha [69]3 years ago
4 0

Answer:

5

Step-by-step explanation:

because there is a perfect triangle ratio thing that is 1: 1: √(2)

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Write an exponential function in the form y=ab^xy=ab x that goes through points (0, 20)(0,20) and (6, 1280)(6,1280).
Phoenix [80]

Answer:

y=20(2)^x

Step-by-step explanation:

We want to write an exponential function that goes through the points (0, 20) and (6, 1280).

The standard exponential function is given by:

y=ab^x

The point (0, 20) tells us that <em>y</em> = 20 when <em>x</em> = 0. Hence:

20=a(b)^0

Simplify:

20=a(1)\Rightarrow a=20

So, our exponential function is now:

y=20(b)^x

Next, the point (6, 1280) tells us that <em>y</em> = 1280 when <em>x</em> = 6. Thus:

1280=20(b)^6

Solve for <em>b</em>. Divide both sides by 20:

64=b^6

Therefore:

b=\sqrt[6]{64}=2

Hence, our function is:

y=20(2)^x

8 0
2 years ago
What is the factored form of x^3-1
polet [3.4K]

Answer:

the factors of x^3-1 are x^3 -1 = (x-1) (x^2 +x+1)\\

Step-by-step explanation:

We need to find factors of x^3 -1

x^3-1 \\(x)^3 -(1)^3\\We \,\, know\,\, a^3 -b^3 = (a-b) (a^2 +ab + y^2) \\So, \,\, using\,\, the \,\, formula\,\,\\Here\,\, a= x \,\,and\,\, b= 1\\(x)^3 -(1)^3 = (x-1) (x^2 +x+1)\\

So, the factors of x^3-1 are x^3 -1 = (x-1) (x^2 +x+1)\\

7 0
3 years ago
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