Question

Write an equation of the line that passes through a pair of points: -5, -2 3, -1

Answer 1

Answer: option B is correct.

Step-by-step explanation:

The equation of a straight line can be represented in the slope-intercept form, y = mx + c

Where c = intercept

Slope, m =change in value of y on the vertical axis / change in value of x on the horizontal axis represent

change in the value of y = y2 - y1

Change in value of x = x2 -x1

y2 = final value of y

y 1 = initial value of y

x2 = final value of x

x1 = initial value of x

The line passes through (- 5, - 2) and (3, - 1),

y2 = - 1

y1 = - 2

x2 = 3

x1 = - 5

Slope,m = (- 1 - - 2)/(3 - - 5) = 1/8

To determine the intercept, we would substitute x = 3, y = - 1 and

m = 1/8 into y = mx + c. It becomes

- 1 = 1/8 × 3 + c

- 1 = 3/8 + c

c = - 1 - 3/8 = - 11/8

The equation becomes

y = x/8 - 11/8

Answer 2

Answer:

b.   y = 1/8 x - 11/8.

Step-by-step explanation:

The slope = rise / run

= (-1 -( -2)) / (3 - (-5))

=   1/ 8.

y = mx + c  where m = the slope and c = the y-intercept, so we have:

y = 1/8 x + c   Substituting  the point  x = 3 and y = -1:

-1 = 1/8 (3) + c

c = -1 - 1/8 (3)

c = -1 3/8 = -11/8