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r-ruslan [8.4K]
4 years ago
5

Solve by completing the square: 6x^2+39=5+12x

Mathematics
1 answer:
Marta_Voda [28]4 years ago
8 0
6x^2-12x=-34
x^2-2x=-34/6
x^2-2x=-17/3

x^2-2x+1= -17/3+1/1
x^2-2x+1= -14/3

(x-1)^2= -14/3
x-1= √-14/3

Final answer: No solution (you cannot find the root of a negative number)
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Find the area of the trapezoid with bases 8 cm and 4 cm and a height of 1/4 cm. (Simplify your answer)
Simora [160]

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1 1/2 or 1.5

Step-by-step explanation:

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How many solutions does this quadratic equation have?<br> 6p^2-7p+5=0
KatRina [158]

Answer:

It has no real solution.

Step-by-step explanation:

6p^2 − 7p + 5 = 0

For this equation: a = 6, b = -7, c = 5

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3 0
4 years ago
Read 2 more answers
In the figure, line m is parallel to line n. The measure of angle 2 is 40 degrees and the measure of angle 3 is 68 degrees. What
sveticcg [70]

Answer:

∠1 - 40°

Step-by-step explanation:

∠1 - 40°

b/c it's a right triangle and we have two angles given, 50° and 90°. Add them and subtract by 180° and get 40°.

∠2 - 140°

b/c an exterior (outside) angle is equal to the two most isolated / farthest angles added. The two most is angles are 105° and 35°, add them and get 140°.

∠3 - 40°

b/c ∠'s 1 and 3 are vertical angles meaning they're equal so since ∠1 is 40°, so is ∠3.

∠4 -

b/c ∠' s 2 and 4 are vertical angles meaning they're equal so since ∠2 is 140°, so is ∠4.

∠5 - 35°

b/c we have two angles, 105° and 40°. Add them and subtract by 180° and get 35°.

hope that helps lol >:)

4 0
3 years ago
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