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Snezhnost [94]
3 years ago
13

Use the quadratic formula to solve 7c^2 + 8c + 1 =0

Mathematics
1 answer:
siniylev [52]3 years ago
4 0
7c² + 8c + 1 = 0
c = <u>-(8) +/- √((8)² - 4(7)(1))</u>
                     2(7)
c = <u>-8 +/- √(64 - 28)</u>
                 14
c = <u>-8 +/- √(36)
</u>              14
c = <u>-8 +/- 6</u>
          14
c = <u>-8 + 6</u>      c = <u>-8 - 6</u>
         14                 14
c = <u>2</u>              c = <u>-14</u>
     14                    14
c = ¹/₇            c = 1

The solution is equal to { 1, ¹/₇}.
<u />
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2(2w - 6) + 2(w) = 3(w + 8)
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Answer:

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Step-by-step explanation:

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3 years ago
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Anna [14]

Answer:

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Step-by-step explanation:

since

x²+y²+z²−8x+4y=−4

we have to complete the squares to finish with a equation of the form

(x-a)²+(y-b)²+(z-c)²=R²

that is the equation of a sphere of radius R and centre in (a,b,c)

thus

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x²+y²+z²−8x+4y +4 = 0

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(x-4)² + (y-(-2))² + (z-0)² = 4²

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3 years ago
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