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DENIUS [597]
3 years ago
13

I was out for math..anyone know how to do this??

Mathematics
2 answers:
Feliz [49]3 years ago
7 0
33

A. No
B. Yes
C. Yes
D. No

34.

4 x (2.75 + 1.25)
$16.00

o-na [289]3 years ago
3 0
35. All you have to do is add the whole numbers and then u add the decimal point, so it would be 12.23.
36. The answer would be 0 because you are multiplying and when u multiply with a 0 the product is always 0.
37.You just have to multiply the numbers together normally and ignore the decimal point, when you are done you just have to move the decimal point over 1 space.

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The amount of time devoted to studying statistics each week by students who achieve a grade of A in the course is a normally dis
svlad2 [7]

Answer:

a) 11.7% of students study for more than 10 hours per week.    

b) 35.6% of student spends between 7 and 9 hours studying.

c) 1.6% of  students spend fewer than 3 hours studying.

d) 5% of all A students spend studying 4.0455 or less hours during a week.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 7.5 hours

Standard Deviation, σ = 2.1 hours

We are given that the distribution of amount of time is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

a) P(students study for more than 10 hours per week)

P(x > 10)

P( x > 10) = P( z > \displaystyle\frac{10 - 7.5}{2.1}) = P(z > 1.1904)

= 1 - P(z \leq 1.1904)

Calculation the value from standard normal z table, we have,  

P(x > 10) = 1 - 0.883 = 0.117 = 11.7\%

b) P(student spends between 7 and 9 hours studying.)

P(7 \leq x \leq 9) = P(\displaystyle\frac{7 - 7.5}{2.1} \leq z \leq \displaystyle\frac{9-7.5}{2.1}) = P(-0.2380 \leq z \leq 0.7142)\\\\= P(z \leq 0.7142) - P(z < -0.2380)\\= 0.762 - 0.406 = 0.356 = 35.6\%

P(7 \leq x \leq 9) = 35.6\%

c)  P(students spend fewer than 3 hours studying)

P(x < 3) = P(z < \displaystyle\frac{3-7.5}{2.1}) = P(z < -2.1428)

Calculating the value from the standard normal table we have,

P( x < 3) =0.016 = 1.6\%

d)  P(X < x) = 0.05

We have to find the value of x such that the probability is 0.035

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Calculation the value from standard normal z table, we have,  

\displaystyle\frac{x - 7.5}{2.1} = -1.645\\x = 4.0455  

5% of all A students spend studying 4.0455 or less hours during a week.

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