Question

WHAT IS THE LENGTH OF EF IN THE RIGHT TRIANGLE BELOW? answers are in the picture !

Answer 1

$Using\ the\ Pythagoreans'\ theorem,\ \\ \\ \\ c^2=a^2+b^2 \\ \\ 25^2=7^2+b^2 \\ \\ b^2=625-49 \\ \\ b= \sqrt{576} \\ \\ = 24\ units$

Answer 2

Answer:

The length of EF in the given right triangle is:

                   Option: B   24

Step-by-step explanation:

We are given a right triangle EFD with base DF=a=7 units.

Height EF=b

and Hypotenuse of the triangle ED=c=25 UNITS.

We know that in a right angled triangle we can apply Pythagorean Theorem.

According to Pythagorean Theorem we have:

$c^2=a^2+b^2\\\\(25)^2=(7)^2+b^2\\\\625=49+b^2\\\\b^2=625-49\\\\b^2=576\\\\b^2=(24)^2$

on taking square root on both side we get:

$b=\pm 24$

But as side of a triangle can't be negative.

Hence,  b= 24 units.