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Studentka2010 [4]
2 years ago
14

WHAT IS THE LENGTH OF EF IN THE RIGHT TRIANGLE BELOW? answers are in the picture !

Mathematics
2 answers:
xeze [42]2 years ago
6 0
Using\ the\ Pythagoreans'\ theorem,\ \\ \\ \\ c^2=a^2+b^2 \\ \\ 25^2=7^2+b^2 \\ \\ b^2=625-49 \\ \\ b= \sqrt{576} \\ \\ = 24\ units
Bezzdna [24]2 years ago
3 0
<h2>Answer:</h2>

The length of EF in the given right triangle is:

                   Option: B   24

<h2>Step-by-step explanation:</h2>

We are given a right triangle EFD with base DF=a=7 units.

Height EF=b

and Hypotenuse of the triangle ED=c=25 UNITS.

We know that in a right angled triangle we can apply Pythagorean Theorem.

According to Pythagorean Theorem we have:

c^2=a^2+b^2\\\\(25)^2=(7)^2+b^2\\\\625=49+b^2\\\\b^2=625-49\\\\b^2=576\\\\b^2=(24)^2

on taking square root on both side we get:

b=\pm 24

But as side of a triangle can't be negative.

Hence,  b= 24 units.

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