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Elanso [62]
3 years ago
11

Triangle ABC has points A(2, -1), B(3, 4), C(-7, 2), and is dilated by a factor of 5 to create the triangle A'B'C'. What are the

coordinates of triangle A'B'C'?
Mathematics
1 answer:
iris [78.8K]3 years ago
5 0

Answer:

A'(10,-5)\\\\B'(15,20)\\\\C'(-35,10)

Step-by-step explanation:

You know that the triangle ABC has these points:

A(2, -1), B(3, 4), C(-7, 2)

If the triangle ABC is dilated by a factor of 5 to create the triangle A'B'C', you can find the coordinates of this new triangle by multiplying by 5 the coordinates of the triangle ABC given.

Therefore, the coordinates of the triangle A'B'C' are:

A'=(2(5),\ -1(5))=(10,-5)\\\\B'=(3(5),\ 4(5))=(15,20)\\\\C'=(-7(5),\ 2(5))=(-35,10)

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To solve this problem, you first would need to solve for how much of the cake is left after Jasmine, her friend, and Jasmine's brother got their slices. Then, you would need to split the remaining amount in half to get the answer of what each parent ate. We would need to make all of the denominators the same, so let's make all of the fractions out of 12, a common denominator of 3 and 4. 

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