Question

Triangle ABC has points A(2, -1), B(3, 4), C(-7, 2), and is dilated by a factor of 5 to create the triangle A'B'C'. What are the coordinates of triangle A'B'C'?

Answer 1

Answer:

$A'(10,-5)\\\\B'(15,20)\\\\C'(-35,10)$

Step-by-step explanation:

You know that the triangle ABC has these points:

A(2, -1), B(3, 4), C(-7, 2)

If the triangle ABC is dilated by a factor of 5 to create the triangle A'B'C', you can find the coordinates of this new triangle by multiplying by 5 the coordinates of the triangle ABC given.

Therefore, the coordinates of the triangle A'B'C' are:

$A'=(2(5),\ -1(5))=(10,-5)\\\\B'=(3(5),\ 4(5))=(15,20)\\\\C'=(-7(5),\ 2(5))=(-35,10)$