Ask question

Ask question

All categories

3 years ago

13

A grain of sand has a mass of 2.6 × 10–3 gram. A grain of salt has a mass of 6.5 × 10–2 gram. How many times greater is the mass

of the grain of salt than the mass of the grain of sand?
A
2.5
B
3.9
C
25
D
39

1 answer:

myrzilka [38]3 years ago

5 0

Answer:

C

Step-by-step explanation:

2.6 x10^-3= .0026

6.5 x10^-2=.065

.065/.0026=25

You might be interested in

The variables A, B, and C represent polynomials where A = x2, B = 3x + 2, and C = x – 3. What is AB – C2 in simplest form?

Vladimir [108]

AB = X^2(3X +2)

C^2 = (x - 3)^2

AB - C^2 = 3x^3 + 2x^2 - (x^2 - 6x + 9)

= 3x^3 + x^2 + 6x - 9

3 0

2 years ago

If triangle EFG is shifted five units to the left, what will be the new coordinates of vertex F?

Papessa [141]

Answer:

A) (-7, 4)

usatestprep

6 0

2 years ago

Ava is making punch for the entire class. She mixed 3 gallons of lemonade with every 7 gallons of Hawaiian Fruit Punch to make t

irina [24]

Answer:

3:7

Step-by-step explanation:

3 parts of lemonade to 7 parts punch

5 0

2 years ago

Read 2 more answers

Homework:Assignment 3 Question 20 Score: 0 of 1 point A vending machine dispenses coffee into -ounce cup. The amount of coffee

xxMikexx [17]

Answer:

19.92

Step-by-step explanation:

To overfill 5% of the time ;

The Zscore (value) to the left of (1 - 0.05) = 0.95 is 1.645

Using this Zscore value with the Zscore formula :

Zscore = (x - μ) / σ

σ = 0.05 ; x = 20 ounce

Substituting into the Zscore formula :

1.645 = (20 - μ) / 0.05

1.645*0.05 = 20 - μ

0.08225 = 20 - μ

μ = 20 - 0.08225

μ = 19.91775

μ = 19.92

8 0

2 years ago

Let log_(b)A=3; log_(b)C=2; log_(b)D=5 what is the value of log_(b)((A^(5)C^(2))/(D^(6)))

Colt1911 [192]

Answer:

-11

Step-by-step explanation:

Given

$\log_bA=3\\ \\\log_bC=2\\ \\\log_bD=5$

Use properties:

$\log_b(A\cdot C)=\log_bA+\log_bC\\ \\\log_b\dfrac{A}{C}=\log_bA-\log_bC\\ \\\log_bA^k=k\log_bA$

Thus,

$\log_b\dfrac{A^5\cdot C^2}{D^6}\\ \\=\log_b(A^5\cdot C^2)-\log_bD^6\\ \\=\log_bA^5+\log_bC^2-\log_bD^6\\ \\=5\log_bA+2\log_bC-6\log_bD\\ \\=5\cdot 3+2\cdot 2-6\cdot 5\\ \\=15+4-30\\ \\=-11$

3 0

2 years ago