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3 years ago

The average daily temperature for July 1910 was 71o F.

Mathematics

1 answer:

Alex17521 [72]3 years ago

4 0

Sorry, but you did not ask any valid question, so I cannot help you figure out an answer.

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Expand . ( 3x –2 ) 2 please help me with this.

Ainat [17]

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Answer: $\textsf{9x}^2\textsf{ - 12x + 4}$

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Given: $\textsf{(3x - 2)}^2$

Find: $\textsf{Simplify the expression}$

Solution: It looks like 2 is at the end of the parenthesis where the power would be instead of distributing the number. If so the following steps would be followed.

Expand

$\textsf{(3x - 2)}^2$

$\textsf{(3x - 2)(3x - 2)}$

$\textsf{(3x * 3x) + (3x * (-2)) + (3x * (-2)) + (-2 * (-2))}$

Simplify

$\textsf{9x}^2\textsf{ - 6x - 6x + 4}$

$\textsf{9x}^2\textsf{ - 12x + 4}$

Therefore, after following the provided information we are able to determine that the expanded form would be 9x^2 - 12x + 4.

3 0

1 year ago

Read 2 more answers

3 x 2 to the power of negative 4

MariettaO [177]

Answer:

3/16

Step-by-step explanation:

2^-4 = 1/2^4 = 1/16

7 0

3 years ago

Read 2 more answers

PLEASE HELP HELP !!!!!!!

german

Answer: The answer is –3x+10=5x–8.

Step-by-step explanation:

5 0

2 years ago

Will get branliest!!!!!!!

lawyer [7]

Answer:

It has the same domain as the function $f(x)=-\sqrt{-x}$

Step-by-step explanation:

we have

$f(x)=\sqrt{-x}$

we know that

The radicand cannot be a negative number

$-x\geq 0$

Solve for x

Multiply by -1 both sides

$x\leq 0$

The domain of the given function is the interval ----> (-∞,0]

All real numbers less than or equal to 0

The range of the given function is the interval ----> [0,∞)

All real numbers greater than or equal to zero

Verify each statement

Part 1) It has the same domain as the function $f(x)=-\sqrt{-x}$

The statement is true

The domain of the function $f(x)=-\sqrt{-x}$ is

the interval ---> (-∞,0]

Part 2) It has the same range as the function $f(x)=-\sqrt{-x}$

The statement is false

The range of the function $f(x)=-\sqrt{-x}$ is

the interval ---> (-∞,0]

Part 3) It has the same domain as the function $f(x)=-\sqrt{x}$

The statement is false

The domain of the function $f(x)=-\sqrt{x}$ is

the interval ---> [0,∞)

Part 4) It has the same range as the function $f(x)=-\sqrt{x}$

The statement is false

The range of the function $f(x)=-\sqrt{x}$ is

the interval ---> (-∞,0]

4 0

3 years ago

Read 2 more answers

Subtract 3/y-2 - 1/y+3

Helen [10]

To subtract fractions, we need a common denominator.

$\frac{3}{y-2}$ - $\frac{1}{y+3}$

the common denominator will be (y-2)(y+3)

$\frac{3(y+3)-1(y-2)}{(y-2)(y+3)}$
$\frac{3y + 9 - y + 2}{(y-2)(y+3)}$
$\frac{2y + 11}{(y-2)(y+3)}$

The answer above will be the simplified form.

3 0

3 years ago