Answer:
the expected rate of change in consumption is 11.83
Step-by-step explanation:
The computation of the expected rate of change in consumption is shown below:
= (Expected quadrillion thermal units - 2003 quadrillion thermal units) ÷ (difference in years)
= (563 - 421) ÷ (2015 - 2003)
= 142 ÷ 12
= 11.83
hence, the expected rate of change in consumption is 11.83
We simply applied the above formula so that the correct value could come
And, the same is to be considered
Hey there!
The answer is no because whenever you add or subtract fractions, you find the common denominator(the bottom of the fraction)
Corret way:
The common denominator is 15 (5*3)
Multiply numerator(top) and the denominator by 3
4/5*3*3= 12/15
Multiply numerator and the denominator by 5
1/3*5/5= 5/15
So the equation is now
12/15+5/15= 17/15 or 1 2/15
Hope this helps! :)
121 is big enough to assume normality and not worry about the t distribution. By the 68-95-99.7 rule a 95% confidence interval includes plus or minus two standard deviations. So 95% of the cars will be in the mph range

The question is a bit vague, but it seems we're being asked for the 95% confidence interval on the average of 121 cars. The 121 is a hint of course.
The standard deviation of the average is in general the standard deviation of the individual samples divided by the square root of n:

So repeating our experiment of taking the average 121 cars over and over, we expect 95% of the averages to be in the mph range

That's probably the answer they're looking for.