Answer:
Aggregation
Explanation:
In Java, Aggregation is a relationshipthat exists between two classes that is best described as a "has-a"
Answer:
The answer to this question is given below in the explanation section.
Explanation:
Almost all app that is doing online business integrated third party payment gateway and login/services. But some apps, don't integrate the third party login/signin services such as go ogle or face book login/sign in services.
But in the context of this question, for a parking payment app, upon reservation of parking space, the pay option connects a user to a third party/external gateway. This gateway will accept payment from the user and upon confirmation of payment, the parking space will get reserved.
so the correct option to this question is:
While the other options are incorrect because:
The sign-in option does not connect the user to a third pay/gateway in case if the app has self-registration and sign-in functionality. Rate and Time remaining are features of the app that does not force the user to connect third-party gateway.
Answer:
I don't know the language this is but here is something that will work for all lang
int num0 = 0;
int num1 = 0;
basically just print the ints in the right dimension
Explanation:
Sorry if I am wrong
I don't know much about this someone else's answer might be better than mine
Answer:
Check the explanation
Explanation:
#include<iostream.h>
#include<stdlib.h>
void append(char* first,int n,char* second, int n1,char* result)
{
int i,j=0;
for(i=0;i<n;i++)
result[i]=first[i];
for(i=n;i<n1+n;i++)
{
result[i]=second[j];
j++;
}
}
void main()
{
char first[]={'I', ' ','a', 'm', ' '};
char second[]={'i', 'r', 'o', 'n', 'm', 'a', 'n','\0'};
char result[200];
append(first,5,second, 8, result);
cout<<result;
cout<<endl;
system("pause");
}
Try {
AutoFactory.shutdown();
} catch (ProductionInProgressException e) {
AutoFactory.reset();
}
