Answer:
Set up for both orders of integration for the integral below where R is the arc of a circle radius 2 in the first quadrant. Show that both orders produce the same result by integrating each of them.
∫ ∫(2x) dA
R
Answer: y= -2x - 4
Step-by-step explanation:
This is a straight line, so it can be expressed by y = mx + c.
Here c is y-intercept, which means where line cuts the y-axis. We can see from the graph that the line cuts the y-axis at -4.
So, c = -4.
m is slope.
Use slope formula to find m.
m = ( -4 - 0 ) / ( 0 -(-2))
m = -4 / 2
m = -2
Now put values into this equation
y = mx + c
y = -2x - 4
Answer:
Rectangle is 224
Step-by-step explanation:
I only know the rectangle im so sorry
7/10 and 14/20 are the equivalent fractions that would solve this equation
Without the instructions, I can only assume that you are to "expand the given expression."
Following order of operations rules requires that (3x-2)^2 and -6(2x-1.5) be evaluated first.
(3x-2)^2 = 9x^2 - 12x + 4 and -6(2x-1.5) = -12x + 9
Then we have 9x^2 - (9x^2 - 12x + 4) -12x + 9
the 9x^2 terms cancel, leaving us with 12x - 4 - 12x + 9 = 5 (answer)
