Answer:
8
Explanation:
![\frac{1}{4}](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B4%7D%20)
cotx – 11 = -9
To solve algebraically, try to get cotx alone.
First, add 11 to both sides:
![\frac{1}{4}](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B4%7D%20)
cotx – 11
+ 11 = -9
+ 11![\frac{1}{4}](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B4%7D%20)
cotx = 2
Now divide by
![\frac{1}{4}](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B4%7D%20)
on both sides, which is the same as multiplying the other side by 4:
![\frac{1}{4}](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B4%7D%20)
cotx ÷
![\frac{1}{4}](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B4%7D%20)
= 2 ÷
cotx = 8
Answer:
PR= 8
ST=5
Step-by-step explanation:
PQ and PR are congruent so
2x=8
x=4
2*4=8
PR=8
ST and TU are congruent so
5z=2z+3
3z=3
z=1
5*1=5
ST=5
Answer:
x
11
Step-by-step explanation:
![8\left(x+1\right)-7x](https://tex.z-dn.net/?f=8%5Cleft%28x%2B1%5Cright%29-7x)
![8x+8-7x](https://tex.z-dn.net/?f=8x%2B8-7x)
![x+8](https://tex.z-dn.net/?f=x%2B8)
Then..
![x+8\ge \:-3](https://tex.z-dn.net/?f=x%2B8%5Cge%20%5C%3A-3)
Subtract 8 from both sides
![x+8-8\ge \:-3-8](https://tex.z-dn.net/?f=x%2B8-8%5Cge%20%5C%3A-3-8)
Then, you got your awnser.
![x\ge \:-11](https://tex.z-dn.net/?f=x%5Cge%20%5C%3A-11)
The fraction with the greater denominator is the greater fraction.