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Kobotan [32]
3 years ago
10

8(x+1)-7x ≥-3 help me find the solution

Mathematics
1 answer:
Ann [662]3 years ago
7 0

Answer:

x \geq 11

Step-by-step explanation:

8\left(x+1\right)-7x

8x+8-7x

x+8

Then..

x+8\ge \:-3

Subtract 8 from both sides

x+8-8\ge \:-3-8

Then, you got your awnser.

x\ge \:-11

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Answer:

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16x + 16x2 = 672

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16x + 16x2 = 672

Solving for variable 'x'.

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Combine like terms: 672 + -672 = 0

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Factor out the Greatest Common Factor (GCF), '16'.

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Factor a trinomial.

16((-7 + -1x)(6 + -1x)) = 0

Ignore the factor 16.

Subproblem 1

Set the factor '(-7 + -1x)' equal to zero and attempt to solve:

Simplifying

-7 + -1x = 0

Solving

-7 + -1x = 0

Move all terms containing x to the left, all other terms to the right.

Add '7' to each side of the equation.

-7 + 7 + -1x = 0 + 7

Combine like terms: -7 + 7 = 0

0 + -1x = 0 + 7

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Combine like terms: 0 + 7 = 7

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Divide each side by '-1'.

x = -7

Simplifying

x = -7

Subproblem 2

Set the factor '(6 + -1x)' equal to zero and attempt to solve:

Simplifying

6 + -1x = 0

Solving

6 + -1x = 0

Move all terms containing x to the left, all other terms to the right.

Add '-6' to each side of the equation.

6 + -6 + -1x = 0 + -6

Combine like terms: 6 + -6 = 0

0 + -1x = 0 + -6

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Combine like terms: 0 + -6 = -6

-1x = -6

Divide each side by '-1'.

x = 6

Simplifying

x = 6

Solution

x = {-7, 6}

Step-by-step explanation:

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