Answer:
= 10x² + 9x³
Step-by-step explanation:
I'm assuming you mean question 19
3x² + 5x³ + 7x² + 4x³ (rearrange to group like terms)
=3x² + 7x² + 5x³ + 4x³ (factor out common powers)
= (3+7)x² + (5+4)x³
= 10x² + 9x³
Answer:
The line equation that passes through the given points is 5x – 2y + 16 = 0
Explanation:
Given:
Two points are A(-2, 3) and B(0, 8).
To find:
The line equation that passes through the given two points.
Solution:
We know that, general equation of a line passing through two points (x1, y1), (x2, y2) is given by

.............(1)
here, in our problem x1 = 0, y1 = 8, x2 = -2 and y2 = 3.
Now substitute the values in (1)



2y – 16 = 5x
5x – 2y + 16 = 0
Hence, the line equation that passes through the given points is 5x – 2y + 16 = 0.
Answer:
y=96
Step-by-step explanation:
Important information:
y=x^2(2+4)
x=4
Explanation/Solution:
y=x^2(2+4)
y=4^2(2+4)
y=16 (2+4)
y= 16 · 6 =
y=96
Here in the second term I am considering 2 as power of x .
So rewriting both the terms here:
First term: 12x²y³z
Second term: -45zy³x²
Let us now find out whether they are like terms or not.
"Like terms" are terms whose variables (and their exponents such as the 2 in x²) are the same.
In the given two terms let us find exponents of each variable and compare them for both terms.
z : first and second term both have exponent 1
x: first and second term both have exponent 2
y: first and second term both have exponent 3
Since we have all the exponents equal for both first and second terms variables, so we can say that the two terms are like terms.
Let X be the number of boys in n selected births. Let p be the probability of getting baby boy on selected birth.
Here n=10. Also the male and female births are equally likely it means chance of baby boy or girl is 1/2
P(Boy) = P(girl) =0.5
p =0.5
From given information we have n =10 fixed number of trials, p is probability of success which is constant for each trial . And each trial is independent of each other.
So X follows Binomial distribution with n=10 and p=0.5
The probability function of Binomial distribution for k number of success, x=k is given as
P(X=k) = 
We have to find probability of getting 8 boys in n=10 births
P(X=8) = 
= 45 * 0.0039 * 0.25
P(X = 8) = 0.0438
The probability of getting exactly 8 boys in selected 10 births is 0.044