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Ilia_Sergeevich [38]
3 years ago
8

Find the midpoint of the line segment with the given endpoints. 1) (-4, -9), (-6, -6)

Mathematics
1 answer:
weeeeeb [17]3 years ago
8 0

Answer:

The answer is

<h2>( - 5 \: , \:  -  \frac{15}{2} )</h2>

Step-by-step explanation:

The midpoint M of two endpoints of a given line segment can be found by using the formula

<h3>M = ( \frac{x1 + x2}{2}  , \frac{y1 + y2}{2} )</h3>

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

(-4, -9), (-6, -6)

The midpoint is

<h3>M = ( \frac{ - 4 - 6}{2}  , \:  \frac{ - 9 - 6}{2} ) \\  = ( -  \frac{10}{2} , -  \frac{15}{2} )</h3>

We have the final answer as

<h3>( - 5 \: , \:  -  \frac{15}{2} )</h3>

Hope this helps you

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Jenny owns a salon. She had 150 customers at the end of the third quarter, 151 customers at the beginning of the third quarter,
Ira Lisetskai [31]

There is a 96% customer retention rate for the third quarter.

Given

Jenny owns a salon.

She had 150 customers at the end of the third quarter, 151 customers at the beginning of the third quarter, and five new customers in the third quarter.

<h3>Customer retention rate</h3>

It determines the percentage of customers that the company has retained over a given period.

The customer retention rate is determined by;

\rm Customer \ retention \ rate=\dfrac{Given \ period -New \ customers}{Initial \ number}\times 100

Substitute all the values in the formula;

\rm Customer \ retention \ rate=\dfrac{Given \ period -New \ customers}{Initial \ number}\times 100\\\\\rm Customer \ retention \ rate=\dfrac{150-5}{151}\times 100\\\\ Customer \ retention \ rate=\dfrac{145}{151}\times 100\\\\ Customer \ retention \ rate=0.96 \times 100\\\\ Customer \ retention \ rate=96

Hence, there is a 96% customer retention rate for the third quarter.

To know more about customer retention rate click the link given below.

brainly.com/question/25668470

7 0
2 years ago
0.346 rounded to the nearest hundredth
Gekata [30.6K]

0.35 is rounded to the nearest hundredth           3would be in the tenth place 4is in the hundredth  place  6is in the thousandths place hope this helps
6 0
2 years ago
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If a third plane could be drawn which contains both lines a and b .
allsm [11]

Answer:

must be parallel

Step-by-step explanation:

They must be parallel.

6 0
3 years ago
8time-5=12time+1 solve the equation
zalisa [80]
1 * 12 = -40
12 = -40

Since its not possible for twelve to equal negative-forty, than there is no answer for this equation.

5 0
3 years ago
If
Svetach [21]
To solve this problem, there is a very simple trick, once you see it. The first step is to subtract the second equation from the first equation. This gives:

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Multiply by 5/3 to get 10x + 10y

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7 0
3 years ago
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