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3 years ago

X^2-2xy+y2 is a polynomial of ___________variable?

Mathematics

2 answers:

Eva8 [605]3 years ago

5 0

Answer:

2 variable x and y ( varable are the symbol that can take any balue in a expression)

fgiga [73]3 years ago

3 0

Answer:

x and y

Step-by-step explanation:

You might be interested in

Sarah took the advertising deparſment from her company on a round trip to meet with a potential client. Including Sarah a total

wlad13 [49]

Answer:

Sarah bought 7 coach tickets and 4 first class tickets.

Step-by-step explanation:

From the information provided, you can write the following equations:

x+y=11 (1)

240x+1100y=6080 (2), where:

x is the number of coach tickets

y is the number of first class tickets

In order to find the value of x and y, first you have to solve for x in (1):

x=11-y (3)

Now, you have to replace (3) in (2) and solve for y:

240(11-y)+1100y=6080

2640-240y+1100y=6080

860y=6080-2640

860y=3440

y=3440/860

y=4

Finally, you can replace the value of y in (3) to find the value of x:

x=11-y

x=11-4

x=7

According to this, the answer is that Sarah bought 7 coach tickets and 4 first class tickets.

7 0

3 years ago

1/3 of a number T is less than or equal to five

ZanzabumX [31]

Answer: x ≤ 15

Step-by-step explanation: All we need to do is divide both sides by 1/3, so1/3x / 1/3 and 5/ 1/3 = 15. So x ≤ 15.

Hope this helps!

8 0

3 years ago

Read 2 more answers

A random sample of 10 parking meters in a beach community showed the following incomes for a day. Assume the incomes are normall

Vlad1618 [11]

Answer: (2.54,6.86)

Step-by-step explanation:

Given : A random sample of 10 parking meters in a beach community showed the following incomes for a day.

We assume the incomes are normally distributed.

Mean income : $\mu=\dfrac{\sum^{10}_{i=1}x_i}{n}=\dfrac{47}{10}=4.7$

Standard deviation : $\sigma=\sqrt{\dfrac{\sum^{10}_{i=1}{(x_i-\mu)^2}}{n}}$

$=\sqrt{\dfrac{(1.1)^2+(0.2)^2+(1.9)^2+(1.6)^2+(2.1)^2+(0.5)^2+(2.05)^2+(0.45)^2+(3.3)^2+(1.7)^2}{10}}$

$=\dfrac{30.265}{10}=3.0265$

The confidence interval for the population mean (for sample size <30) is given by :-

$\mu\ \pm t_{n-1, \alpha/2}\times\dfrac{\sigma}{\sqrt{n}}$

Given significance level : $\alpha=1-0.95=0.05$

Critical value : $t_{n-1,\alpha/2}=t_{9,0.025}=2.262$

We assume that the population is normally distributed.

Now, the 95% confidence interval for the true mean will be :-

$4.7\ \pm\ 2.262\times\dfrac{3.0265}{\sqrt{10}} \\\\\approx4.7\pm2.16=(4.7-2.16\ ,\ 4.7+2.16)=(2.54,\ 6.86)$

Hence, 95% confidence interval for the true mean= (2.54,6.86)

7 0

3 years ago

Find the total value of an investment of $1030 at 4% for 2 years to the nearest dollar.

mel-nik [20]

Answer:

1114$

Step-by-step explanation:

3 0

2 years ago

usa el teorema de la altura para proponer como se podria construir un segmento cuya longitud sea media proporcional entre dos se

Mrac [35]

Usando el teorema de altura

El teorema de altura relaciona la altura (h) de un triángulo rectángulo (ver figura) y los catetos de dos triángulos que son semejantes al anterior ABC, al trazar la altura (h) sobre la hipotenusa. De manera que en todo triángulo rectángulo, la altura (h) relativa a la hipotenusa es la media geométrica de las dos proyecciones de los catetos sobre la hipotenusa (n y m). Es decir, se cumple que:

 $\frac{n}{h}= \frac{h}{m}$

Dado que el problema establece construir un segmento cuya longitud sea media proporcional entre dos segmentos de 4 y 9 cm, entonces, digamos que n = 4cm y m = 9cm tenmos que:

 $\frac{4}{h}= \frac{h}{9}$

De donde:

$h= \sqrt{(4)(9)}=\sqrt{36}=6cm$

¿Cómo se podria construir si los segmentos son de a cm y b cm?

Si los segmentos son de a y b cm entonces a y b son parámetros que pueden tomar cualquier valor positivo siempre que se cumpla que:

$h= \sqrt{ab}$

6 0

2 years ago