The absolute value of
5.23 = l5.23l
Answer:
1
Step-by-step explanation:
1 times anything is itself
you're welcome
The value of x is 1.
The value of y is 4.
Solution:
Given TQRS is a rhombus.
<u>Property of rhombus:
</u>
Diagonals bisect each other.
In diagonal TR
⇒ 3x + 2 = y + 1
⇒ 3x – y = –1 – – – – (1)
In diagonal QS
⇒ x + 3 = y
⇒ x – y = –3 – – – – (2)
Solve (1) and (2) by subtracting
⇒ 3x – y – (x – y) = –1 – (–3)
⇒ 3x – y – x + y = –1 + 3
⇒ 2x = 2
⇒ x = 1
Substitute x = 1 in equation (2), we get
⇒ 1 – y = –3
⇒ –y = –3 – 1
⇒ –y = –4
⇒ y = 4
The value of x is 1.
The value of y is 4.
Answer:
:) :D
Step-by-step explanation:
2x + 5y = 2
-3x - y =-3
-3x - y = -3
y = 3x - 3
substitute y = 3x - 3 into the first equation.
2x + 5y = 2
2x + 5(3x - 3) = 2
2x + 15x - 15 = 2
17x - 15 = 2
solve for x in 17x - 15 = 2
17x - 15 = 2
17x = 2 + 15
17x = 17
x = 1
substitute x = 1 into y = 3x - 3
y = 3x - 3
y = 3(1) - 3
y = 3 - 3
y = 0
(1, 0) << the answer
hope this helped, God bless!
